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3 years ago

These tables represent continuous functions. In which table do the values represent an exponential function.

Mathematics

2 answers:

Neporo4naja [7]3 years ago

8 0

The answer for this question is c

Dennis_Churaev [7]3 years ago

4 0

If you look at all 4 of these tables. Exponential means a large increase or gradual increase so. With that in mind if you look at table 1, the y column only increases by 5. For B, the y column only increases by 1. For C, the y column increase by 4 then 8 then 16 then 32. Therefore it is exponential. For D it is consistently an increase of 8.

Hope this helps!

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Kruka [31]

It’s 8 u cross multiply 7 and 1 then 1 and 56 and then divide 56 by 7

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3 years ago

Write a rule in coordinate form for the translation from Triangle EFG to Triangle

DanielleElmas [232]

Answer:

1st option

Step-by-step explanation:

Consider the coordinates of F and F'

F (- 3, 4 ) and F' (- 1, 3 )

To go from - 3 → - 1 in the x- directions , means adding 2

To go from 4 → 3 in the y- direction means subtracting 1

Then translation rule is

(x, y ) → (x + 2, y - 1 )

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3 years ago

Under her cell phone plan, Aubrey pays a flat cost of $57.50 per month and $4 per gigabyte . She wants to keep her bill at $75.1

docker41 [41]

Answer:

57.50+4x=75.10

x=4.4

So she can use up to 4.4 gigabytes of data

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3 years ago

What is the slope of the line that passes through the points (-8, -3)(−8,−3) and (-12, -3) ?(−12,−3)? Write your answer in simpl

Darya [45]

Answer:

$\\ \frac{y2 - y1}{x2 - x1} = \frac{ - 3 - ( - 3)}{ - 12 - ( - 8)} = \frac{ - 3 + 3}{ - 12 + 8} = 0 \div ( - 4) = 0$

6 0

2 years ago

Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0

2 years ago