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anzhelika [568]
3 years ago
14

Two numbers are in a ration of 3:7, the larger exceeds the smaller by 12.

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
7 because that’s just the right answer duhhhhhhh
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Ewans flight is schheduled to travel 1,750 in 3.5 hours . at what rate does it travel per hour
Karo-lina-s [1.5K]

Answer:

It travel at the rate of <u>500 miles per hour</u>.

Step-by-step explanation:

Given:

Ewans flight is scheduled to travel 1,750 miles in 3.5 hours.

Now, to find the rate it travel per hour.

Distance = 1,750 miles.

Time = 3.5 hours.

So, to get the rate we put formula:

Speed=\frac{distance}{time}

Speed=\frac{1750\ miles}{3.5\ hours}

Speed=500\ miles\ per\ hour

Therefore, it travel at the rate of 500 miles per hour.

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3 years ago
Amelia rented a dvd and it was due to be returned on 26 novmeber
kap26 [50]
You need to ask the question not a bit of dialogue xx
8 0
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A man travels 600km partly by train and partly by car. If he covers 400km by train and the rest by car, it takes him 6 hours and
11Alexandr11 [23.1K]

Answer:

A man travels 600km partly by train and partly by car. If he covers 400km by train and the rest by car, it takes him 6 hours and 30 minutes. But if he travels 200 km by train and rest by car, he takes half an hour longer.find the speed of the train and that of the car

Step-by-step explanation:

4 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





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