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meriva
3 years ago
14

Giving branliest

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

5(x+10)^-30-(-5) = 0

5(x+10)^-30+5=0

5x + 50 + 5 = 0

5x + 55 = 0

5x = -55

x = -55

-----

5

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Answer:

D

Step-by-step explanation:

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Ernesto solves the equation below by first squaring both sides of the equation. \sqrt{\dfrac{1}{2}w+8}=-2 2 1 ​ w+8 ​ =−2square
algol [13]

Answer:

<h2>w = -8</h2>

Step-by-step explanation:

Given the equation solved by Ernesto expressed as \sqrt{\dfrac{1}{2}w+8}=-2, the extraneous solution obtained by Ernesto is shown below;

\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8

Hence, the extraneous solution that Ernesto obtained is w = -8

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