In other words, how many ways are there to choose
Help me with this question please
1 answer:
Answer:
D. 2019
Step-by-step explanation:
So I started by rewriting the function f(x)
1000 = 10^3 so
f(x)=10^3 times 1.03^x
1.03 = 103/100 so
f(x)= 10^3 times (103/100)^x
to raise a fraction to a power you just raise the numerator and denominator to that power so
f(x)= 10^3 times 103^x/100^x
change it to exponential form with a base of 10
f(x)=10^3 times 103^x/10^2x
then you can reduce it with the 10^3
f(x)=103^x/10^2x-3
so now that thats in more of a standard form you can find the intersection of the two functions
which is at (9.012,1305.244)
x is the number of years after 2010, so they will be equal ~9 years after 2010, which is 2019.
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In other words, how many ways are there to choose
Answer:
a)
And for this case we can rewrite the model like this:
If we integrate both sides we got:
If we use exponentials for both sides we got:
For this case and r = -0.16
So then our model would be given by:
Where t represent the number of hours
b)
Step-by-step explanation:
Part a
For this case we can assume the proportional model given by:
And for this case we can rewrite the model like this:
If we integrate both sides we got:
If we use exponentials for both sides we got:
For this case and r = -0.16
So then our model would be given by:
Where t represent the number of hours
Part b
For this case we can replace the value t=5 into the model and we got: