A lion with a mass of 190 kg is chasing a gazelle with a mass of 15 kg. The distance between the lion and the gazelle is 2 meter
1 answer:
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The height of the building is 53.4 m (projectile motion)
Explanation:
The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:
where:
is the horizontal velocity of the ball, which is constant since there are no forces in this direction
d = 165 m is the horizontal distance travelled by the ball
Solving for t, we find the time of flight:
Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation
where
s is the vertical displacement, which is the height of the building
u = 0 is the initial vertical velocity of the ball
t = 3.3 s is the time of flight
is the acceleration of gravity
Solving for s, we find the height of the building:
Learn more about projectile motion here:
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Answer:
a) V = -0.227 mV
b) V = -0.5169 mV
Explanation:
a)
Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude
E = (qr) / (4πε₀R³)
As we know that
V = -
By solving above equation, we get
V = (-qr²) / (8πε₀R³)
When
R = 1.81 cm
r = 1.2 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)
V = -2.27 × 10⁻⁴ V
V = -0.227 mV
b)
When
r = R
R = 1.81 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-qR²) / (8πε₀R³)
V = (-q) / (8πε₀R)
V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))
V = -5.169 × 10⁻⁴ V
V = -0.5169 mV