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3 years ago

Which cell structure is found in plant cells, but not in animal cells?

Physics

2 answers:

Mazyrski [523]3 years ago

8 0

Answer:

Cell wall and chloroplasts (only for leaves)

Explanation:

All plant cells have cell walls to give the cell a fixed shape but animal cells do not have cell walls. Some cells like leaf cells have chloroplasts to make their own food for the plant while animal cells do not have chloroplasts.

andre [41]3 years ago

5 0

Answer:

chloroplasts

Explanation:

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A box of bananas weighing 40.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surfa

nataly862011 [7]

Answer:

a) $f=0\ N$

b) $f=6\ N$

c) $F=16\ N$

d) $a=2.45\ m.s^{-2}$

Explanation:

Given:

weight of the box on the horizontal surface, $w=40\ N$

coefficient of static friction between the surface and the box, $\mu_s=0.2$

coefficient of kinetic friction between the surface and the box, $\mu_k=0.2$

When no horizontal force acts on the box then according to the Newton's first law of motion there will be no any force of friction acting on the body but just a vertical component is balanced by the normal reaction.

Now force on the box, $F=6\ N$

So there we have the maximum force of static friction as:

$f_s=\mu_s.N$

here:

N = normal force equal to the weight of the body

$f_s=0.4\times 40$

$f_s=16\ N$

Now the magnitude of the static frictional force is equal to the applied force on the box. So,

$f=6\ N$

Since we have the maximum static frictional force between the two surfaces as:

$f_s=16\ N$

So, the applied force must be equal to this limiting value.
So the applied force must be:

$F=16\ N$

Now when the box has started its motion then the minimum intensity of the force to keep the box moving is equals to the kinetic frictional force:

$F_k=\mu_k.N$

$F_k=0.2\times 40\\F_k=8\ N$

The value of friction force:

Since the box is moving, so the maximum friction is the kinetic friction:

$F_k=8\ N$

The applied force is :

$F=18\ N$

So the acceleration will be due to :

$\Delta F=F-F_k$

$\Delta F=10\ N$

now we know that:

$a=\frac{\Delta F}{m}$

$a=10\div\frac{40}{9.8}$

$a=2.45\ m.s^{-2}$

8 0

3 years ago

In the periodic table, the properties repeat in what direction?

pogonyaev

Answer:

Left to right and top to bottom

Explanation:

On the periodic table, the properties repeat from left to right and from top to bottom.

Periodic properties have a pattern from the top to the bottom or down a group or family.

Also, across the period from left to right, they also show a repeating pattern.

Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.

7 0

3 years ago

Suggest two uses of pulleys.

Marizza181 [45]

Answer: Elevators use pulleys to function.

A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.

Explanation:

8 0

3 years ago

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the a

Sveta_85 [38]

F = M a

= (0.5) (3)

= 1.5 newtons

4 0

4 years ago

Read 2 more answers

A particle is confined between rigid walls separated by a distance L = 0.167 nm. The particle is in the second excited state (n

ZanzabumX [31]

Answer:

The answer for a classical particle is 0.00595

Explanation:

The equation of the wave function of a particle in a box in the second excited state equals:

ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)

The probability is equal to:

P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx

for x = 0.166 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3

for x = 0.028 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3

for x = 0.067 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3

therefore, the classical probability is equal to:

(1/L)dx = (1/0.167)*100 pm = 0.00595

8 0

3 years ago