Answer:
a) 
b) 
c) 
d) 
Explanation:
Given:
weight of the box on the horizontal surface, 
coefficient of static friction between the surface and the box, 
coefficient of kinetic friction between the surface and the box, 
a)
When no horizontal force acts on the box then according to the Newton's first law of motion there will be no any force of friction acting on the body but just a vertical component is balanced by the normal reaction.
b)
Now force on the box, 
So there we have the maximum force of static friction as:

here:
N = normal force equal to the weight of the body


- Now the magnitude of the static frictional force is equal to the applied force on the box. So,

c)
Since we have the maximum static frictional force between the two surfaces as:

- So, the applied force must be equal to this limiting value.
- <u>So the applied force must be:</u>
<u />
<u />
d)
Now when the box has started its motion then the minimum intensity of the force to keep the box moving is equals to the kinetic frictional force:


e)
The value of friction force:
Since the box is moving, so the maximum friction is the kinetic friction:

The applied force is :

<u>So the acceleration will be due to :</u>





Answer:
Left to right and top to bottom
Explanation:
On the periodic table, the properties repeat from left to right and from top to bottom.
Periodic properties have a pattern from the top to the bottom or down a group or family.
Also, across the period from left to right, they also show a repeating pattern.
- Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
- Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.
Answer: Elevators use pulleys to function.
A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.
Explanation:
Answer:
The answer for a classical particle is 0.00595
Explanation:
The equation of the wave function of a particle in a box in the second excited state equals:
ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)
The probability is equal to:
P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx
for x = 0.166 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3
for x = 0.028 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3
for x = 0.067 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3
therefore, the classical probability is equal to:
(1/L)dx = (1/0.167)*100 pm = 0.00595