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ankoles [38]
3 years ago
9

Which cell structure is found in plant cells, but not in animal cells?

Physics
2 answers:
Mazyrski [523]3 years ago
8 0

Answer:

Cell wall and chloroplasts (only for leaves)

Explanation:

All plant cells have cell walls to give the cell a fixed shape but animal cells do not have cell walls. Some cells like leaf cells have chloroplasts to make their own food for the plant while animal cells do not have chloroplasts.

andre [41]3 years ago
5 0

Answer:

chloroplasts

Explanation:

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A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

\mu = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

\omega = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0
4 years ago
A tank of liquid (SG=0.80) that is 1 ft in diameter and 1.0 ft high is rigidly fixed to a rotating arm having a 2 ft radius. The
IgorLugansk [536]

Answer:

the pressure at B is 527psf

Explanation:

Angular velocity, ω = v / r

ω = 20 /1.5

= 13.333 rad/s

Flow equation from point A to B

P_A+rz_A-\frac{1}{2} Pr_A^2w^2=P_B+rz_B-\frac{1}{2} pr^2_Bw^2\\\\P_B = P_A + r(z_A-z_B)+\frac{1}{2} pw^2[(r_B^2)-(r_A)^2]\\\\P_B = [25 +(0.8+62.4)(0-1)+\frac{1}{2}(0.8\times1.94)\times(13.333)^2[2.5^2-1.5^2]  ]\\\\P_B = 25 - 49.92+551.79\\\\P_B = 526.87psf\\\approx527psf

the pressure at B is 527psf

6 0
3 years ago
The combustion of ethanol, C2H5OH(l), in oxygen to form carbon dioxide gas and water vapor is shown by which balanced chemical e
NemiM [27]
C2H5OH (l) + 3 O2 (g) = 2 CO2 (g)+ 3 H2O (l/g)
4 0
3 years ago
A 65kg person throws a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the
asambeis [7]

Answer:

v₁ = 2.48m/s, v₂ = 0.02m/s

Explanation:

Momentum p must be conserved. p = mv

1) First person throwing the snow ball. The momentum before the throw:

p = (65kg + 0.045kg) * 2.5 m/s

The momentum after the throw:

p = 65kg * v₁ + 0.045kg * 30m/s

Solving for the velocity v₁ of person 1:

v₁ = ((65kg + 0.045kg) * 2.5 m/s - 0.045kg * 30m/s) / 65kg = 2.48m/s

2) Second person catching the ball. The momentum before the catch:

p = 0.045kg * 30m/s + 60kg * 0m/s

The momentum after the catch:

p = (60kg + 0.045kg) * v₂

Solving for velocity v₂ of person 2:

v₂ = 0.045kg * 30m/s / (60kg + 0.045kg) = 0.02 m/s

5 0
3 years ago
Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law​
ehidna [41]

Answer:

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Explanation:

7 0
3 years ago
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