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WITCHER [35]
3 years ago
8

A shopping mall has a length of 200 m and a width of 75 m. What is the area of the mall?

Physics
1 answer:
sweet [91]3 years ago
6 0
To find the area, we just need to multiply the length by the width. 200 x 75 = 15,000. The mall has an area of 15,000 sq. feet.
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Ohms law? explanation.​
shusha [124]

Answer:

\boxed{ \bold{ \sf{see \: below}}}

Explanation:

\boxed{ \bold{ \underline{ \huge{  \boxed{ \sf{ohm's \: law}}}}}}

The relation between current through a metallic conductor and potential difference across its ends was studied systematically by a German physicist , <u>George </u><u>Simon </u><u>Ohm </u> in <u>1</u><u>8</u><u>2</u><u>6</u><u> </u><u>AD </u>. This relation is now known as Ohm's law. It states that <u>the </u><u>electric </u><u>current </u><u>passing </u><u>through</u><u> </u><u>a </u><u>conductor </u><u>is </u><u>directly </u><u>proportional</u><u> </u><u>to </u><u>the </u><u>potential </u><u>difference</u><u> </u><u>across </u><u>its </u><u>two </u><u>ends </u><u>at </u><u>a </u><u>constant </u><u>physical </u><u>condition</u><u> </u><u>[</u><u> </u><u>Temperature</u><u> </u><u>,</u><u> </u><u>cross </u><u>-</u><u> </u><u>sectional </u><u>area </u><u>,</u><u> </u><u>length </u><u>,</u><u> </u><u>nature </u><u>of </u><u>material </u><u>etc </u><u>]</u>

Hope I helped!

Best regards!!

4 0
4 years ago
By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and
puteri [66]

Answer:

14.8 kg

Explanation:

We are given that

m_1=43.7 kg

m_2=12.1 kg

g=9.8 m/s^2

a=\frac{1}{2}(9.8)=4.9 m/s^2

We have to find the mass of the pulley.

According to question

T_2-m_2 g=m_2 a

T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N

T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N

Moment of inertia of pulley=I=\frac{1}{2}Mr^2

(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)

Where \alpha=\frac{a}{r}

(177.87-214.13)=-\frac{1}{2}(4.9)M

-36.26=-\frac{1}{2}(4.9)M

M=\frac{36.26\times 2}{4.9}=14.8 kg

Hence, the mass of the pulley=14.8 kg

6 0
3 years ago
A(n) 28.3 g bullet is shot into a(n) 5004 g wooden block standing on a frictionless surface. The block, with the bullet in it, a
Natali [406]

Answer:

the speed of the bullet before striking the block is 302.3 m/s.

Explanation:

Given;

mass of the bullet, m₁ = 28.3 g = 0.0283 kg

mass of the wooden block, m₂ = 5004 g = 5.004 kg

initial velocity of the block, u₂ = 0

final velocity of the bullet-wood system, v = 1.7 m/s

let the initial velocity of the bullet before striking the block = u₁

Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.

m₁u₁  +  m₂u₂  =  v(m₁  +  m₂)

0.0283u₁  + 5.004 x 0   =  1.7(0.0283  +  5.004)

0.0283u₁   =   8.5549

u₁ = 8.5549 / 0.0283

u₁ = 302.3 m/s

Therefore, the speed of the bullet before striking the block is 302.3 m/s.

4 0
3 years ago
Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

v_f^2=v_i^2+2ax

Where,

v_f = Final velocity

v_i = Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

F_f = \mu_k (mg)  \rightarrowFrictional Force

F = ma \rightarrow Force by Newton's second Law

Where,

m = mass

a= acceleration

\mu_k = Kinetic frictional coefficient

g = Gravity

Equating both equation we have that

F_f = F

\mu_k mg=ma

a = \mu_k g

Therefore,

v_f^2=v_i^2+2ax

0=v_i^2+2(\mu_k g)x

Re-arrange to find x,

x = \frac{v_i^2}{2(-\mu_k g)}

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

3 0
3 years ago
One of the principal difficulties in establishing the theory of continental drift (the idea that tectonic plates drift around on
iragen [17]

Answer:

The energy that drives this movement is heat within the earth, this heat comes from two main sources which are;

1) residual heat left over from the formation of our planet billions of years ago.

2) The radioactive decay of naturally occurring chemical elements (notably uranium, thorium, and potassium ) in the earth releases energy in the form of heat. These two sources of heat warm Earth’s mantle and cause it to rise and sink, this rising and sinking creates a convectional movement of earth mantle.

4 0
4 years ago
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