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2 years ago

8

A shopping mall has a length of 200 m and a width of 75 m. What is the area of the mall?

1 answer:

sweet [91]2 years ago

6 0

To find the area, we just need to multiply the length by the width. 200 x 75 = 15,000. The mall has an area of 15,000 sq. feet.

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Upper A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f

Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the wall.

The attached figure shows whole description such that,

$x^2+y^2=256$ .........(1)

$\dfrac{dx}{dt}=2\ ft/s$

We need to find, $\dfrac{dy}{dt}$ at x = 5 ft

Differentiating equation (1) wrt t as :

$2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0$

$2x+y\dfrac{dy}{dt}=0$

$\dfrac{dy}{dt}=-\dfrac{2x}{y}$

Since, $y=\sqrt{256-x^2}$

$\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}$

At x = 5 ft,

$\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}$

$\dfrac{dy}{dt}=0.65$

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0

3 years ago

What’s Chemical energy

AVprozaik [17]

Answer:

Chemical energy is energy that chemical substance to undergoes a chemical reaction to make a new substance.

Explanation:

<h3>hope this makes sense and helps</h3>

5 0

3 years ago

Read 2 more answers

What is the speed of sound in air at 40°C?

Blababa [14]

343 meters per second Is the answer

4 0

3 years ago

Read 2 more answers

A car travels 45 km due north and 70 km west. What is the car's displacement? 6 points 24.7 km northeast 83.2 km northwest 76.5

HACTEHA [7]

Answer:

3150

Explanation:

if if you were two times 45 times 70 it would give you that answer

8 0

3 years ago

Water ice has a density of 0.91 g/cm2, so it will float in liquid water. Imagine you have a cube of ice, 10 cm on a side. a. Wha

Reptile [31]

Answer:

(i) W = 8.918 N

(ii) $V = 9.1 \times 10^{-4} m^3$

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

$W = mg$

$W = \rho V g$

here we know that

$\rho = 0.91 g/cm^3$

$Volume = L^3$

$Volume = 10^3 = 1000 cm^3$

now the mass of the ice cube is given as

$m = 0.91 \times 1000 = 910 g$

now weight is given as

$W = 0.910 \times 9.8 = 8.918 N$

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

$W_{displaced} = 8.918 N$

So here volume displaced is given as

$\rho_{water}Vg = 8.918$

$1000(V)9.8 = 8.918$

$V = 9.1 \times 10^{-4} m^3$

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

$W = \rho_{water} (L^2 d) g$

$8.918 = 1000(0.10^2 \times d) 9.8$

$d = 0.091 m$

so it is submerged by d = 9.1 cm inside water

4 0

3 years ago