3 years ago

Which of the following is the correct order of the polynomial 4x^ 2 -6x^ 4 -x+2x^ 5 +1?

Mathematics

1 answer:

Anettt [7]3 years ago

3 0

4x^2-6x^4+2x^5-x+1 is the correct order

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Jeffrey's brother max is 5 years older than twice Jeffrey's age. Write an expression that represents the relationship of Max's a

Illusion [34]

Jeffrey = J
Max = M

M = 2j + 5

4 0

3 years ago

What’s MA I need a answer asap if possible

choli [55]

Answer:

Step-by-step explanation:

MA²=MX²+AX²

=20²+21²

=400+441

=841

MA=√841=29

8 0

2 years ago

Read 2 more answers

Un observador se encuentra en un faro al pie de un acantilado a 687m sobre el nivel del mar, desde este punto observa un barco c

maks197457 [2]

La distancia entre el barco y la base del acantilado es 291.61 metros.

<h3>¿Como calcular la distancia?</h3>

Podemos pensar en esta situacion como en un triangulo rectangulo. Uno de los catetos mide 687 metros, que es la altura del acantilado.

Y conocemos el angulo al que ese cateto es adjacente, que mide 23 grados.

La distancia entre la base del acantilado y el barco será el otro cateto del triangulo rectangulo.

Entonces podemos usar la relación:

tan(a) = (cateto opuesto)/(cateto adjacente)

Reemplazando lo que sabemos:

tan(23°) = D/687m

tan(23°)*687m = D = 291.61m

La distancia entre el barco y la base del acantilado es 291.61 metros.

Sí quieres aprender más sobre triangulos rectangulos:

brainly.com/question/2217700

#SPJ1

8 0

2 years ago

A 16 ounce bag of cereal cost $2.88 what is the cost per ounce

BabaBlast [244]

Answer: 0.18 (18 cents) per ounce

Step-by-step explanation:

2.88/16 = 0.18

5 0

3 years ago

The radius of a right circular cylinder is increasing at the rate of 3 ft/sec, while the height is decreasing at the rate of 6 f

goblinko [34]

Answer:

$\frac{dV}{dt}=-450\pi ft^3/sec$

Step-by-step explanation:

Let's assume

radius of cylinder as 'r'

height of cylinder as 'h'

so, we have

$\frac{dr}{dt} =3ft/sec$

$\frac{dh}{dt} =-6ft/sec$

r=15ft

h=10ft

now, we can use volume of cylinder formula

$V=\pi r^2h$

we can find derivative with respect to t

$\frac{dV}{dt}=2\pi r h\times\frac{dr}{dt} +\pi r^2\times \frac{dh}{dt}$

now, we can plug values

$\frac{dV}{dt}=2\pi (15)(10)\times3 +\pi (15)^2\times -6$

now, we can simplify it

$\frac{dV}{dt}=-450\pi ft^3/sec$

6 0

3 years ago