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lisabon 2012 [21]
3 years ago
15

At India’s arcade 2/3 of the games are racing games. Among the racing games, 1/2 are motorcycle racing games. What fraction of t

he games at India’s arcade are motorcycle racing games
Mathematics
1 answer:
OleMash [197]3 years ago
7 0

Answer:

\frac{1}{3}

Step-by-step explanation:

Motorcycle racing games = \frac{1}{2} × \frac{2}{3} (Directly multiply)

                                           = \frac{2}{6} (Simplify)

                                           = \frac{1}{3} (Tada!)

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Find the explicit formula for -3,-33,-63,-93
bagirrra123 [75]

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a n = -3+(n-1)-30

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-3 - 30 = -33

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How should I go about solving this question?
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2 years ago
The product of 7 and 0.04 is 0.28.<br><br> [True]<br><br> or<br><br> [False]
tino4ka555 [31]
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Read 2 more answers
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
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3 years ago
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