Please help, our teacher wasn’t here and we got no explanation on how to do it
2 answers:
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Given:
Point is T(-3,8).
To find:
The coordinates of T' after .
Solution:
We know that, means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then
If a figure reflected across y-axis, then
Therefore, the required point is T'(3,-8).
Anwers:
1. line A
2. line D
3. line B
4. line C
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the original function:
f(x) = 10x
and g(x) = a · 10x is the general from of all transformed functions from the above original function.
- p(x) = 4 · 10x
The graph of this function is stretched vertically => line A
- q(x) = –4 · 10x
The graph of this function is stretched vertically and is reflected through the x-asix => line D.
- r(x) = (1/4) x 10x
The graph of this function is compressed vertically => line B
- s(x) = (-1/4) x 10x
The graph of this function is compressed vertically and is reflected through the x-asix => line C
Hope it will find you well.
