1. 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
2. CH₄ + 2O₂ → CO₂ + 2H₂O
3. Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
4. MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂
5. Pb(NO₃)₂ + 2NaCl → PbCl₂ + 2NaNO₃
1)
2)
CuSO_4+Cu_2Cl_2\neq>
Answer:
2.45Joules
Explanation:
since kinetic energy is K.E.=1/2m
lost in potential energy is gain of kinetic energy
mgh=1/2mv^2
9.8*2*0.5=v^2
=9.8
v=
=3.13m/s
now k.e. = 0.5*m* =0.5*0.5*9.8 =2.45J
Answer:
Explanation:
The nitrates of Bi,Sn and Cd is ruled out because their sulfides are insoluble in acidic medium.
Nitrates of Ni or Co may be present because their sulfides are insoluble in basic medium. The presence of other nitrates are ruled out.
Answer:
hey listen I'll hate to take the pts and go but I have to do what a man have to do
Explanation:
The equation of the reaction is given as;
12C + 16 H2 --> 4 C3H8
a. Simplify the equation;
The coefficients are 12, 16 and 4.
4 is a common factor, so divide all through by 4.
12/4 = 3, 16/4 = 4, 4/4 = 1
The equation is given as;
3 C + 4 H2 --> C3H8
b. If 21 moles of C3H8 are formed, how many moles of C was needed.
From the reaction;
3 mol C atoms reacts to form 1 mol of C3H8
x mol would react to form 21 moles of C3H8
3 = 1
x = 21
x = 21 * 3
x = 63 moles
