8 moles Cl to grams 3

G in your own words, summarize the issue of ocean acidification: what is it and what's causing it?

AleksandrR [38]

Ocean acidification refers to a reduction in the pH of the ocean over an extended period of time, caused primarily by the uptake of carbon dioxide (CO2) from the atmosphere.

Because of human-driven increased levels of carbon dioxide in the atmosphere, there is more CO2 dissolving into the ocean. The ocean's average pH is now around 8.1, which is basic (or alkaline), but as the sea continues to absorb more CO2, the pH decreases and the ocean becomes more acidic.

How does ocean acidification affect us?

Ocean acidification can modify the abundance and chemical composition of harmful algal blooms in such a way that shellfish toxicity increases and, therefore, human health are negatively affected.

How we can reduce ocean acidification?

The most effective way to limit ocean acidification is to act on climate change, implementing solutions to dramatically reduce the use of fossil fuels. If we dramatically cut our global warming emissions, and we limit future warming, we can significantly reduce the harm to marine ecosystems.

To know more about ocean acidification:

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8 0

1 year ago

If 0.750 L of argon at 1.50 atm and 177°C and 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C are added to a 1.00-L flask and t

Furkat [3]

Answer:

The resulting pressure in the flask is 0.93 atm

Explanation:

- Apply the Ideal Gas law in both cases to get the mols, of Ar and SO2.

- Once you know the mols, sum both to get the total mols in the mixture.

- Apply the Ideal Gas lawin the flask with the total mols to know the resulting pressure.

First: 0.750 L of argon at 1.50 atm and 177°C

T° C + 273 = T° K → 177°C + 273 = 450K

P .V = n . R . T

1.50 atm . 0.750 L = n . 0.082 L.atm/mol.K . 450K

(1.50 atm . 0.750 L) / (0.082 mol.K/L.atm . 450K) = n

0.030 mols Ar = n

Be careful with the R units, the ideal gases constant

Let's convert kPa to atm.

101.33 kPa _____ 1 atm

95 kPa ________ (95 / 101.33) = 0.94 atm

T° C + 273 = T° K → 63°C + 273 = 336 K

0.94 atm . 0.235 L = n . 0.082 L.atm/mol.K . 336K

(0.94 atm . 0.235 L) / (0.082 mol.K/L.atm . 336K) = n

8.01X10⁻³ mols = n

0.030 mols Ar + 8.01X10⁻³ mols SO₂ = 0.038 total mols in the mixture

1L . P = 0.038 mol . 0.082 L.atm / mol.K . 298 K

P = (0.038 mol . 0.082 L.atm / mol.K . 298 K ) / 1L

P = 0.93 atm

7 0

2 years ago

Solids , liquids are the three different states of matter However , they show some similarities of their properties

frozen [14]

Answer:

1 may is the answer for the question

6 0

2 years ago

Li Ming thinks that chlorophyll is a reactant of photosynthesis, but her classmate Julian disagrees. Who is correct, and why?

Eddi Din [679]

Julian is correct because chlorophyll is neither used up nor formed in the chemical reaction of photosynthesis.

Explanation:

Julian is correct because chlorophyll is neither used up nor formed in the chemical reaction of photosynthesis. The reactants in photosynthesis are carbon dioxide and water.

Photosynthesis is the process by which green plants manufacture their food in the presence of sunlight.
In photosynthesis carbon dioxide combines with water to produce glucose and oxygen.
Chlorophyll in plant is a green pigment that is used to trap sunlight during photosynthesis.

Learn more:

Photosynthesis brainly.com/question/2761166

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7 0

2 years ago

Read 2 more answers

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

$A=\pi ^{1/3} (6V)^{2/3}$

The area of the 10.0 cm³-sphere is:

$A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}$

The area of each 1.25 cm³-sphere is:

$A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}$

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

6 0

3 years ago