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Citrus2011 [14]

2 years ago

12

Hey this is juelz gautreaux parent and she has a hard time on math so i got brainly for her and does not work

2 answers:

Anvisha [2.4K]2 years ago

7 0

Answer:

Hey! so glad you got this to help your child. I believe this will help them alot, but this is not like a social media app.... don't post things like this unless needed but i hope you enjoy your time here.

Step-by-step explanation:

Andrew [12]2 years ago

4 0

Answer:

try looking the question up on here

Step-by-step explanation:

if you look up the question word for word on here, (if not exactly)usually there will be a similar problem answered, and use that to base your help off of when working on a hard problem

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If you choose one student at random, what is the probability (±0.0001) that the student's score is between 20 and 30?

nordsb [41]

Z-score for 30 = (30 - 25) / 5.8 = 0.8621
z-score for 20 = (20 - 25) / 5.8 = -0.8621
:
Note find probabilities from z-tables
:
Probability ( 20 < X < 30 ) = 0.8051 - 0.1949 = 0.6102

5 0

2 years ago

Estimate the measure of

Lelu [443]

Answer:

148°

Step-by-step explanation:

it is very close to the 150 line and the option closest to 150 is 148

8 0

3 years ago

Read 2 more answers

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Need help! Please answer!

deff fn [24]

8 1/4 is given as a positive number so you could write it as +8 1/4

The opposite of positive is negative, so you would have -(+8 1/4)

The answer is A

8 0

3 years ago

The sum of two numbers is 19. The difference is 9. What are the two numbers?

Nostrana [21]

Answer:

the two numbers are 8 and 8

7 0

2 years ago

Read 2 more answers