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Citrus2011 [14]
3 years ago
12

Hey this is juelz gautreaux parent and she has a hard time on math so i got brainly for her and does not work

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
7 0

Answer:

Hey! so glad you got this to help your child. I believe this will help them alot, but this is not like a social media app.... don't post things like this unless needed but i hope you enjoy your time here.

Step-by-step explanation:

Andrew [12]3 years ago
4 0

Answer:

try looking the question up on here

Step-by-step explanation:

if you look up the question word for word on here, (if not exactly)usually there will be a similar problem answered, and use that to base your help off of when working on a hard problem

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What is 0.968 as a square root
Juliette [100K]

Answer:

0.98386991

0.9839

Step-by-step explanation:

\sqrt{0.968 }

6 0
3 years ago
Four more than a number is 27
son4ous [18]

Answer:

23 is the answer of the question

3 0
3 years ago
Read 2 more answers
Help me with this 1,2,3. For each sequence, Determine with whether it appears to be arithmetic If it does find a common differen
pshichka [43]

Problem 1

<h3>Answer: Arithmetic, common difference = -4</h3>

-------------------

Explanation:

Pick any term of the sequence, and subtract off the previous term to find that,

  • term2 - term1 = -12 - (-8) = -12 + 8 = -4
  • term3 - term2 = -16 - (-12) = -16 + 12 = -4
  • term4 - term3 = -20 - (-16) = -20 + 16 = -4

Each time we get the same result, so that means we have an arithmetic sequence with common difference -4

This indicates that adding -4 to each term, or subtracting 4 from each term, will generate the next one.

Eg: term2 = term1 - 4 = -8-4 = -12.

==========================================================

Problem 2

<h3>Answer: Arithmetic, common difference = 5</h3>

-------------------

Explanation:

Similar to problem 1, this sequence is also arithmetic because we add on 5 to each term to get the next one

  • -6+5 = -1
  • -1+5 = 4
  • 4+5 = 9

Or you could subtract adjacent terms as done in problem 1, to find that the common difference is 5.

==========================================================

Problem 3

<h3>Answer: Not arithmetic</h3>

-------------------

Explanation:

Unlike the previous two problems, this sequence is not arithmetic.

We can see that

  • term2 - term1 = 12 - 3 = 9
  • term3 - term2 = 48 - 12 = 36

The gaps of 9 and 36 aren't the same. We need the same common difference between any adjacent terms to have an arithmetic sequence.

This sequence is instead geometric because

  • term2/term1 = 12/3 = 4
  • term3/term2 = 48/12 = 4
  • term4/term3 = 192/48 = 4

Each quotient is 4, showing the common ratio is 4. To find the next term, we multiply the current term by 4. So the next term after 192 would be 4*192 = 768, then 4*768 = 3072 is next, and so on.

3 0
3 years ago
HELP!! What is the approximate measure of angle x in the triangle shown?
Alex Ar [27]
<h3>Answer:   D)  130.5 degrees</h3>

=================================================

Work Shown:

c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\

Note: I used the law of cosines. Make sure your calculator is in degree mode.

6 0
3 years ago
Q.23 Prove that: (sin4A - cos4A + 1) = 2sin2A
FrozenT [24]

Answer:

Step-by-step explanation:

I think you have the question incomplete, and that this is the complete question

sin^4a + cos^4a = 1 - 2sin^2a.cos^2a

To do this, we can start my mirroring the equation.

x² + y² = (x + y)² - 2xy,

This helps us break down the power from 4 to 2, so that we have

(sin²a)² + (cos²a)² = (sin²a + cos²a) ² - 2(sin²a) (cos²a)

Recall from identity that

Sin²Φ + cos²Φ = 1, so therefore

(sin²a)² + (cos²a)² = 1² - 2(sin²a) (cos²a)

On expanding the power and the brackets, we find that we have the equation proved.

sin^4a + cos^4a = 1 - 2sin^2a.cos^2a

4 0
3 years ago
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