please help me. In the circle below, U is the center, VX is a diameter, and m VW = 110 degrees Use this information to fill in t
he blanks.
1 answer:
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Answer:
Area of shaded region = 16π in² (D)
Step-by-step explanation:
The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.
Area of the smaller circle = 8π in²
Area of a circle = πr²
πr² = 8π
r² =8
r = √8 = 2√2
From the diagram, there are two smaller circles in a bigger circle.
The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)
R = 2r
Area of bigger circle = πR²
= π×(2r)² = π×(2×2√2)²
= π×(4√2)² = π×16×(√2)²
Area of bigger circle = π×16×2
Area of bigger circle = 32π in²
Since there are two smaller circles in a bigger circle
Area of shaded region = Area of bigger circle -2(area of smaller circles)
Area of shaded region = 32π in² - 2(8π in²)
Area of shaded region = 32π in² - 16π in²
Area of shaded region = 16π in²
<h2>Perfect Squares</h2>
Perfect square formula/rules:
Trinomials are often organized like .
The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.
- Perfect square trinomial:
- or
We're given:
In a trinomial, we're given the and
values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:
- 4 ÷ 2 = 2
- 2² = 4
Therefore, the term that we can add is + 4.
To write this as the square of a bracketed expression, we can follow the rule :