Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
A positive number
This is because you must add to get from a negative number in order to get to a positive number.
See the picture attached to better understand the problem
we know that
in the right triangle ABC
sin 70°=opposite side angle 70°/hypotenuse
in this problem
opposite side angle 70°=AB
hypotenuse=AC----> 32 ft
sin 70°=AB/32------> AB=32*sin 70°-----> AB=30.07 ----> AB=30.1 ft
Answer:
x = 20
Step-by-step explanation:
The angles shown are alternate exterior angles.
Alternate exterior angles are congruent
This means that 46 must equal 3x - 14
Note that we've just created an equation that we can use to solve for
We now use the equation to solve for x
3x - 14 = 46
add 14 to both sides
3x - 14 + 14 = 46 + 14
simplify
3x = 60
Divide both sides by 3
3x / 3 = x
60 / 3 = 20
We get that x = 20
In order to add these fractions we have to make a common denominator.
1/5 can turn into 2/10 Its the same thing. And its easier to solve with.
now lets multiply.
× 
Now we add across
2 + 1 = 3
------------
10 + 10 = 10 ( When adding fractions like these the denominator stays the same)
So your answer is...

Good Luck! :)