The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5
To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5
y= (3 over (x-7)) then minus 5
0.06p = 0.72
p = 12
The original price was $12.
I believe that y is equal to -5.
y=-5
Answer:
D.
Step-by-step explanation:
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Logarithmic Differentiation [Derivative Rule - Chain Rule]:

- Trigonometric Differentiation [Derivative Rule - Chain Rule]:

- Basic Power Rule:

- Rewrite [Trigonometric Identities]:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation