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kodGreya [7K]
3 years ago
14

Find the missing side of the triangle.

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

Approximately 8.1 km

Step-by-step explanation:

Pythagoream Theorem:

{7}^{2}  +  {4}^{2}  =  {x}^{2}  \\ 49 + 16 =  {x}^{2}  \\ 65 =  {x}^{2}  \\  \sqrt{65}  = x \\ 8.1 = x

Hope this helps!!

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Write an equation of the translation of y=3/x with asymptotes of x=7 and y= -5
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The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5

To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5

y= (3 over (x-7)) then minus 5
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Casey’s buys a bracelet she pays for the bracelet and pays 0.72 on sales tax the sales tax rate 6%
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0.06p = 0.72

p = 12
The original price was $12.

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What is the value of y in the equation 2 + y = −3?
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3 years ago
Find the derivative of ln(cosx²).​
RoseWind [281]

Answer:

\displaystyle \frac{dy}{dx} = -2x \tan (x^2)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = \ln (\cos x^2)

<u>Step 2: Differentiate</u>

  1. Logarithmic Differentiation [Derivative Rule - Chain Rule]:                       \displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}
  2. Trigonometric Differentiation [Derivative Rule - Chain Rule]:                   \displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}
  3. Basic Power Rule:                                                                                         \displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}
  4. Rewrite [Trigonometric Identities]:                                                              \displaystyle y' = -2x \tan (x^2)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

8 0
3 years ago
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