(((x + y) / 3) + (1 / x)) / (5 + (15 / x))
The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
((x(x + y)) + 3(1)) / (5(3x) + 3(15))
(x^2 + xy + 3) / (15x + 45)
Then factor to simplify
(x^2 + xy + 3) / (3(x + 15))
Answer:
B) The margin of error is 0.0269.
C) The confidence interval is (0.5406, 0.5944).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

In the poll, n=918 and x=521 who said "yes."
This means that 
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
B) Identify the value of the margin of error E.


The margin of error is 0.0269.
C) construct the confidence interval.

So


The confidence interval is (0.5406, 0.5944).
Answer:
ikaw mag sagut nyan tiba may utak ka? Tanga kaya mo na yan
Step-by-step explanation:
She's imperfect but she tries
She is good but she lies
She is hard on herself
She is broken and won't ask for help
She is messy but she's kind
She is lonely most of the time
She is all of this mixed up
And baked in a beautiful pie
She is gone but she used to be mine
Answer:
Step-by-step explanation:
![2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}](https://tex.z-dn.net/?f=2%28x-2%29%5E2%3D8%287%2By%29%5C%5C2%28x-2%29%5E2%3D56%2B8y%20%5CRightarrow%20y%3D%7B1%5Cover%7B8%7D%7D%5B2%28x-2%29%5E2-56%5D%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Cfinally%5C%5Cy%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Clet%20~change~x~and~y%5C%5Cx%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2-7%5C%5Cx%2B7%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2%5C%5C4%28x%2B7%29%3D%28y-2%29%5E2%5C%5Cy-2%3D%5Cpm%5Csqrt%7B4%28x%2B7%29%7D%5C%5C%5C%5Cy%3D2%5Cpm%5Csqrt%7B4x%2B28%7D)
Answer:
The player's height is 3.02 standard deviations above the mean.
Step-by-step explanation:
Consider a random variable <em>X</em> following a Normal distribution with parameter <em>μ</em> and <em>σ</em>.
The procedure of standardization transforms individual scores to standard scores for which we know the percentiles (if the data are normally distributed).
Standardization does this by transforming individual scores from different normal distributions to a common normal distribution with a known mean, standard deviation, and percentiles.
A standardized score is the number of standard deviations an observation or data point is above or below the mean.
The standard score of the random variable <em>X</em> is:

These standard scores are also known as <em>z</em>-scores and they follow a Standard normal distribution, i.e. <em>N</em> (0, 1).
It is provided that the height of a successful basketball player is 196 cm.
The standard value of this height is, <em>z</em> = 3.02.
The <em>z</em>-score of 3.02 implies that the player's height is 3.02 standard deviations above the mean.