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dlinn [17]
3 years ago
10

He loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a p

ile driver? Round to the nearest ten.
Mathematics
2 answers:
andrey2020 [161]3 years ago
5 0

Answer:

40

Step-by-step explanation:

Edge 2020

chubhunter [2.5K]3 years ago
3 0

Complete question :

The loudness of a jack hammer is 96 dB. Its sound intensity is about 0.004.

The loudness of a compactor is 94 dB. Its sound intensity is about 0.0025.

The sound intensity of the jack hammer is about 1.6 times the sound intensity of the compactor.

The loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a pile driver? Round to the nearest ten.

Answer:

40

Step-by-step explanation:

Given that:

Sound intensity of jackhammer = 0.004

Sound intensity of compactor = 0.0025

Sound intensity of jackhammer is about 1.6 times the sound intensity of a compactor

Each factor of 10 in intensity corresponds to 10dB

Pile driver with loudness of 112dB ; 112 / 10 = 11.2

Hence, 10^11.2 = 1.58489 * 10^11

Hence, sound intensity (I) in watts per m²

I = 1.58489 * 10^11 * 10^-12

I = 1.58489 * 10-1

I = 0.158489

Comparing the intensity of pile driver and jackhammer :

Intensity of piledriver / Intensity of jackhammer

0.158489 / 0.004

= 39.622

= 40 (nearest ten)

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8 0
3 years ago
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jolli1 [7]

Answer:

-914

Step-by-step explanation:

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4 0
4 years ago
Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a
Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature  delta(t1) = 10 degrees

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we'll solve for the ratio of delta(t) / delta(t1)

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The 50   gram mass rises 10 degrees.

7 0
3 years ago
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marshall27 [118]

Answer:

24.3 units (3 s.f.)

Step-by-step explanation:

Since a square has 4 equal sides,

perimeter of ABCD= 4(length of AB)

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perimeter of ABCD

= 4 \sqrt{37}  \\  = 24.3 \: units \: (3 \: s.f.)

7 0
3 years ago
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