A Porsche will always win no matter what
1.
m = mass of Mr. Ure = 65 kg
g = acceleration due to gravity = 9.8 m/s²
force of earth's gravity on Mr. Ure is given as
F = mg
F = 65 x 9.8
F = 637 N
2.
F = force of gravity on car = 3050 N
m = mass of the car = ?
g = acceleration due to gravity = 9.8 m/s²
force of gravity on car is given as
F = mg
3050 = m (9.8)
m = 3050/9.8
m = 311.22 kg
3.
m = mass of Mr. Rees = 90 kg
g = acceleration due to gravity = 9.8 m/s²
force of earth's gravity on Mr. Rees is given as
F = mg
F = 90 x 9.8
F = 882 N
Answer:
Value of electric field along the axis and equitorial axis 
and 
respectively.
Explanation:
Given :
Distance between charges , 
Magnitude of charges , 
Dipole moment , 
Case A) (x,y) = (12.0 cm, 0 cm) :
Electric field of dipole in its axis ,
Putting all values and 
We get , 
Case B) (x,y) = (0 cm, 12.0 cm) :
Electric field of dipole on equitorial axis ,
Putting all values and
We get , 
Hence , this is the required solution.
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Mechanical energy
I think
