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Rainbow [258]
3 years ago
6

One of the primary goals of the Kepler space telescope is to search for Earth-like planets. Data gathered by the telescope indic

ates the existence of one such planet named Boralis orbiting a star 135 ly from our solar system. Consider an interstellar spaceship leaving Earth to travel to Boralis. The ship can reach 0.80c almost instantly and can also decelerate almost instantly. The ship is 143 m long in its reference frame.
1. What is the length of the moving ship (in m) as measured by observers on Earth?


2. How much time (in years) will it take for the spaceship to travel from Earth to Boralis, as measured by an observer on Earth?


3. How much time (in years) will it take for the spaceship to travel from Earth to Boralis, as measured by astronauts in the spaceship?
Physics
1 answer:
amid [387]3 years ago
8 0

Answer:

85.62 m

168.75 years

101.04 years

Explanation:

L_0 = Length of ship = 143 m

v = Velocity of ship = 0.8c

c = Speed of light

s = Distance to Boralis orbit = 135 ly

Gamma value

\gamma=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \gamma=\dfrac{1}{\sqrt{1-\dfrac{0.8^2c^2}{c^2}}}\\\Rightarrow \gamma=1.67

Length contraction is given by

L=\dfrac{L_0}{\gamma}\\\Rightarrow L=\dfrac{143}{1.67}\\\Rightarrow L=85.62\ m

The length is 85.62 m

Time taken

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{135}{0.8}\\\Rightarrow t=168.75\ years

Time taken from the perspective one Earth is 168.75 years

Time dilation is given by

t'=\dfrac{t}{\gamma}\\\Rightarrow t'=\dfrac{168.75}{1.67}\\\Rightarrow t'=101.04\ years

The time taken from the perspective of the ship is 101.04 years

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A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler
nasty-shy [4]

Answer:

Q = 169 BTU

Explanation:

As we know that volume is given as

V = 12 Fl oz

so it is given in liter as

V = 12 fl oz = 0.355 Ltr

now we have six pack of such volume

so total volume is given as

V = 6\times 0.355 Ltr

V = 2.13 ltr

so its mass is given as

m = 2.13 kg

now the change in temperature is given as

\Delta T = 70 - 34 = 36 ^oF

\Delta T = 20^oC

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4 0
3 years ago
a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = 100/\pi m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

#SPJ4

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