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3 years ago

What is the impact of roller coaster on human's body

Physics

1 answer:

Sindrei [870]3 years ago

8 0

Explanation:

These brain chemicals, including adrenaline, dopamine and cortisol, stimulate a natural high and give you a boost of energy that makes you feel more alert, alive and able to scream your lungs out

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A star is a ___ that emits energy produced by nuclear reactions in its interior.

grigory [225]

A star is a large ball of gas that emits energy produced by nuclear reactions in the star's interior. Much of this energy is emitted as electromagnetic radiation, including visible light. Light emitted by stars enables other objects in the universe to be seen by reflection.

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4 years ago

Sort the balloons based on the kinds of charges they carry.

Arte-miy333 [17]

first one is negative

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3 years ago

The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific

dmitriy555 [2]

<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

$KineticEnergy=\frac{1}{2}mv^{2}$

Where,

m, is the mas of the object

v, is the speed of the object.

Now, we are given:

$mass=m=6.8kg\\speed=v=5\frac{m}{s}$

So, substituting and calculating the kinetic energy of the object, we have:

$KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}$

$KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})$

$KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}$

$KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J$

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0

3 years ago

Read 2 more answers

A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.

mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

$m_sv_s + m_bv_b = 0$

where $m_s = 2500 kg, m_b = 25 kg$ are masses of the ship and ball respectively. $v_s = 0.25 m/s, v_b$ are the velocities of the ship and ball respectively, after the shooting.