Is the relationship linear?

What is the area of this parallelogram? 10.35 cm² 12.5 cm² 20.25 cm² 30.6 cm² Parallelogram A B C D is composed of a square and

Taya2010 [7]

Answer:

30.6 cm²

Step-by-step explanation:

The area of the parallelogram is simply the sum of the areas of the component three shapes - the square and the two triangles.

Area of square = 4.5 cm × 4.5 cm = 20.25 cm²

Area of two triangles = 2 ×(1/2) × 2.3 cm × 4.5 cm = 10.35 cm²

Area of parallelogram = 20.25 cm² + 10.35 cm² = 30.6 cm²

5 0

3 years ago

Read 2 more answers

Brainliest 25pts Bad answers = insta-report, if you dont understand dont answer the question. Must give statement and reason

Klio2033 [76]

9514 1404 393

Explanation:

We can find the slope by solving for y.

3x +2y +7 = 5x +3y +10

-2x -3 = y . . . . . . . . . . . . . add -5x-10-2y to both sides of the equation

In this form, the slope (m) is the coefficient of x, -2. Hence m = -2.

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<em>Alternate solution</em>

A graph of the equation shows it has an x-intercept of -1.5 and a y-intercept of -3. The slope (m) is then "rise" divided by "run", or ...

m = rise/run = -3/1.5

m = -2

4 0

2 years ago

Find the value of each variable in the parallelogram

Anarel [89]

Answer:

x = 9

y = 15

Step-by-step explanation:

x = 9

y = 15

I'm not sure how to explain this, but one side is equal to its opposite side in a parallelogram.

Hope this helps :)

5 0

2 years ago

24. A political discussion group consists of 30 Republicans,

Makovka662 [10]

Answer:

12 /67

Step-by-step explanation:

I added everything up to get 67 then I added independent and green together to get 12

7 0

2 years ago

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Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

2 years ago