The force of friction is given in the scenario:
Force = 500 Newton
and the mass of the runner is 60 kg
To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:
Where 'F' represents the force, 'm' represents the mass, and 'a' represents the acceleration.
Plugging the value of variables we get:
Solving for 'a' (acceleration) we get:
Newton/kilogram or meters/ second squared
So the acceleration of the runner is 8.33 meters/ second squared.
Answer:
The possible numbers of hours Justin could rent the boat (0, 40/6]
Step-by-step explanation:
Let t represents the number of hours the boat is used,
∵ The boat costs 6 per hour,
So, the original cost of boat = 6t
Now, after getting $ 4 off
Final cost = 6t - 4
Now, final cost ≤ $ 36
Also, number of hours can not be negative
⇒ t ≥ 0
But, he must use the boat ⇒ t ≠ 0
Hence, the possible numbers of hours Justin could rent the boat,
Answer:
There are 67626 ways of distributing the chairs.
Step-by-step explanation:
This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).
The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, .
For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is .
For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have ways of making the distribution.
As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.