Between 4 and 6 is where u put the grouping symbols!
Answer:
Step 1 is incorrect.
Step-by-step explanation:
The given expression is :

In step 1, Deepak rearranged the terms in order to simplify like terms together that is followed in step 2.
o, rearranging of the terms of an expression is commutative property and not distributive property. The distributive property is generally applicable to multiplication and is given as:

The commutative property is given as:
x+y = y +a
Therefore, adding terms by changing their order is commutative property of addition and not distributive property. Step 1 instruction is wrong.
Answer:
The "check your answer" probably means check your answer by graphing.
Step-by-step explanation:
Answer:
0.7361
Step-by-step explanation:
In this question we have
number to be 10
Then we have a probability of 10% = 0.10
We have q = 1-p
= 1-0.10 = 0.90
Then the probability of not more than 1 being defective:
P(x=0) + p(x= 1)
(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)
= 1 x1 x0.3487 + 10 x 0.1 x 0.3874
= 0.3487 + 0.3874
= 0.7361
This is the the required probability and this answers the question.
probability = 10 percent = 0.1
q= 1- 10percent = 90% = 0.9
n = 4
To get the required probabiltiy for this question is
P(not greater than one is defective )=P(x=0)+P(x=1)
= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³
= 0.9477
The required probability is 0.9477
Answer:

Step-by-step explanation:
In the diagram below we have
ABCD is a parallelogram. K is the point on diagonal BD, such that

And AK meets BC at E
now in Δ AKD and Δ BKE
∠AKD =∠BKE ( vertically opposite angles are equal)
since BC ║ AD and BD is transversal
∠ADK = ∠KBE ( alternate interior angles are equal )
By angle angle (AA) similarity theorem
Δ ADK and Δ EBK are similar
so we have


( ABCD is parallelogram so AD=BC)
( BC= BE+EC)


( subtracting 1 from both side )

taking reciprocal both side
