Select ALL 4 ways of displaying a relation.

ra1l [238]

When you solve the inequality, you will write down all the x values that satisfy the inequality but they have to be integers. The n is x, it is just a common variable used to help describe what kind of numbers they want.

3 0

3 years ago

A doctor gives a patient a 6060% chance of surviving bypass surgery after a heart attack. if the patient survives the surgery,

DENIUS [597]

Let BS be the event that the patient survives bypass surgery. Let H be the event that the heart damage will heal. Then P(BS) = 0.60, and also we have a conditional probability: GIVEN that the patient survives, the probability that the heart damage will heal is 0.5, that is P(H|BS) = 0.5 We want to know P(BS and H). Using the formula of the conditional probability: P(H and BS) = P(H|BS)·P(BS) = (0.6)(0.5) = 0.3

3 0

3 years ago

Suppose that a wall is constructed from concrete blocks where a block is a normal random variable with mean 11 kg and standard d

Artemon [7]

Answer:

The value for k is about k = 11.093kg.

Step-by-step explanation:

To answer this question, that is, P(x<k) = 0.85, we can use the standardized value for a raw score, or the formula for obtaining z-scores:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

$\\ x$ is the raw score.

$\\ \mu$ is the population mean.

$\\ \sigma$ is the population standard deviation.

In this case, we are asking to find a value x = k, so that 85% of the blocks have weights less than k (kg).

We have also to use the values for the cumulative standard normal distribution with $\\ \mu = 0$ and $\\ \sigma = 1$ to find the value of z that corresponds to a probability of 0.85.

First step: find the z that corresponds to the probability of 0.85.

To use the formula [1], as we previously mentioned, we first need to find the value of z that corresponds to a probability of 0.85 using the cumulative standard normal distribution table (available in any Statistics books or on the Internet). Then, for a cumulative probability of 0.85, the corresponding value for z = 1.03 (approximately).

Second step: solve the formula [1] for x.

Solving this formula for x, we have:

$\\ z = 1.03$