Answer:
Explanation:
- State of benzene at RTP = liquid
- State of chloroform at RTP = liquid
- Boiling point of benzene = 80.1 °C
- Boiling point of chloroform = 61.2 °C
Since, both of the chemicals are liquids, we can separate it by the process of distillation.
<u>Distillation:</u>
- is the process in which we separate two liquids on the basis of their difference in boiling points.
<u>How it works:</u>
Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.
- Apparatus of distillation is in the attached file.
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Answer:
1.9×10^20
Explanation:
ϕ = number of reaction events /number of photons absorbed
ϕ= 0.26
Energy= power× time
885×10^-3×10×60= 531J
But E= nhc/λ
n= number of photons
h= planks constant
c= speed of light
λ= wavelength
n= Eλ/hc
n= 531×280×10^-9/6.6×10^-34 ×3×10^8
n= 7.5×10^20
Therefore
From
ϕ = number of reaction events /number of photons absorbed
Number of reaction events= 0.26×7.5×10^20
= 1.95×10^20
Answer:
121.37 moles.
Explanation:
Always one mole of any molecule contains Avogadro number of molecules.
So one mole of methane contains 6.023*10^23 molecules.
Now we need number of moles of methane in 7.31*10^25 molecules.
This is just cross multiplication stuff.
6.023*10^23 molecules —————- 1 mole
7.31*10^25 molecules ——————- ?
= (7.31*10^25) / (6.023*10^23)
= 121.37 moles.
Answer:
0.125
Explanation:
i took a test and got it right choosing this answer hopes this help
Answer:
C₂ = 0.056 ppm
Explanation:
Given data:
Initial volume = 2.0 mL
Initial concentration = 7.0 ppm
Final volume = 250.0 mL
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ = Final volume
Now we will put the values in formula.
C₁V₁ = C₂V₂
7.0 ppm × 2.0 mL = C₂ × 250.0 mL
C₂ = 14.0 ppm.mL /250.0 mL
C₂ = 0.056 ppm
