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Illusion [34]
2 years ago
15

How will you separate a solution of benzene and chloroform?

Chemistry
1 answer:
Troyanec [42]2 years ago
7 0

Answer:

\huge\boxed{\sf Distillation}

Explanation:

  • State of benzene at RTP = liquid
  • State of chloroform at RTP = liquid
  • Boiling point of benzene = 80.1 °C
  • Boiling point of chloroform = 61.2 °C

Since, both of the chemicals are liquids, we can separate it by the process of distillation.

<u>Distillation:</u>

  • is the process in which we separate two liquids on the basis of their difference in boiling points.

<u>How it works:</u>

Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.

- Apparatus of distillation is in the attached file.

\rule[225]{225}{2}

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A solution is prepared by dissolving a
goldfiish [28.3K]

Answer:

119g

Explanation:

Just multiply

2.38% of 500 =

119 g

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3 years ago
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What are the uses of glycerin?<br>​
Ilia_Sergeevich [38]

Explanation:

This medication is used as a moisturizer to treat or prevent dry, rough, scaly, itchy skin and minor skin irritations (e.g., diaper rash, skin burns from radiation therapy). Emollients are substances that soften and moisturize the skin and decrease itching and flaking.

6 0
3 years ago
Calculate the concentration of OH- in a solution that contains 3.9 x 10-4 M H3O+ at 25°C. Identify the solution as acidic, basic
aalyn [17]

Answer:

[OH⁻] = 2,6x10⁻¹¹

Acidic

Explanation:

The kw in water is:

2 H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)

kw = [OH⁻] [H₃O⁺] = 1,00x10⁻¹⁴

If concentracion of H₃O⁺ is 3,9x10⁻⁴M:

[OH⁻] [3,9x10⁻⁴M] = 1,00x10⁻¹⁴

<em>[OH⁻] = 2,6x10⁻¹¹</em>

pH is defined as - log[H₃O⁺]. If pH>7,0 the solution is basic, if pH<7,0 solution is acidic, if pH=7,0 solution is neutral.

In this problem,

pH = - log [3,9x10⁻⁴M] = <em>3,4</em>

As pH is < 7.0, the solution is <em>acidic</em>

<em></em>

I hope it helps!

8 0
3 years ago
What energy is stored
denis-greek [22]

Answer: potential energy is stored

Explanation:

3 0
3 years ago
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
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