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mrs_skeptik [129]
3 years ago
12

A single atom of oxygen cannot be subdivided into simpler substances by any physical or chemical means. Therefore, it is:

Chemistry
2 answers:
Zigmanuir [339]3 years ago
8 0
Qn1)d
qn2)b
qn3)a
qn4)a
Goshia [24]3 years ago
7 0
1) D. An element
2) D. Suspension
3) A. Iodine
4) A. Atoms of the same element
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3 years ago
If you take Organic Chemistry Laboratory (CHM2211L) you will learn the term reflux. A reaction is considered to be at reflux whe
shutvik [7]

Answer : The temperature of the chloroform will be, 101.67^oF

Explanation :

First we have to calculate the mass of chloroform.

\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g

conversion used : (1cm^3=1ml)

Now we have to calculate the temperature of the chloroform.

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat or energy = 1.46 kJ = 1460 J   (1 kJ = 1000 J)

c = specific heat capacity = 0.96J/g.K

m = mass of substance = 110.958 g

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get:

1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K

T_{final}=311.706K

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

^oC=\frac{5}{9}\times (^oF-32)

As we know that, K=^oC+273 or, K-273=^oC

K-273=\frac{5}{9}\times (^oF-32)

K=\frac{5}{9}\times (^oF-32)+273  ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

311.706K=\frac{5}{9}\times (^oF-32)+273

T_{final}=101.67^oF

Therefore, the temperature of the chloroform will be, 101.67^oF

5 0
3 years ago
Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +
Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0
3 years ago
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GaryK [48]

Answer:

The flame test is used to visually determine the identity of an unknown metal or metalloid ion based on the characteristic color the salt turns the flame of a Bunsen burner.

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Which statement is true?
mihalych1998 [28]
B. Most rocks are composed of single mineral
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