C = 12 g
O = 16 g
H = 1 g
<h3>Further explanation
</h3>
Conservation of mass stated that
<em>In a closed system, the masses before and after the reaction are the same
</em>
we can calculate the mass of each atom in the compound :
O in O₂ :
mass O₂ = 32
mass O = 32 : 2 = 16 g
H in H₂O
mass H₂O = 18
mass 2.H + mass O = 18
mass 2.H + 16 = 18
mass 2.H=2
mass H = 1 g
C in CH₄
mass CH₄ = 16
mass C + mass 4.H = 16
mass C + 4.1=16
mass C = 12 g
or we can use formula :
Mass of a single C :

12 times breathe give 240 ml of pure
. Each breathe gives 20 ml of
.
Let us consider, volume of air per breathe= x ml.
Pure
from inhaled air=
ml and Pure
from exhaled air=
ml.
Pure
from inhaled and exhaled air= 20 ml
So,
+
= 20
Therefore, x = 55.5 ml
So, volume of air per breath= 55.5 ml.
Answer:
85% of 20 is 17
Explanation:
You can multiply 85% and 20 or subtract 85% from 20.
High tide or Neap tides which are normally really high.
D. It has almost no hydrogen ions, therefore it is very basic.