Answer :
The basic rules for naming of hydrocarbons are :
First select the longest possible carbon chain.
The longest possible carbon chain should include the carbons of double or triple bonds.
The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne.
The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.
If two or more similar alkyl groups are present in a compound, the prefixes di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.
Answer:
watering flowers with dirty dishwater.
Answer:
NaOH: 22.99 + 16.00 + 1.008 = 40.00 g/mol
H₂O: 2(1.008) + 16.00 = 18.02 g/mol
C₆H₁₂O₆: 6(12.01) + 12(1.008) + 6(16.00) = 180.2 g/mol
CaSO₄: 40.08 + 32.06 + 4(16.00) = 136.1 g/mol
Mg₃(PO₄)₂: 3(24.33) + 2(30.97) + 8(16.00) = 262.9 g/mol
The numbers I added up are the atomic numbers you can find on the periodic table. Multiply the atomic numbers by however many atoms of a element you have.
Answer:
Unit cells which are present per cubic centimeter of Ag = 
Volume = 
Edge length = 
Explanation:
(a)
Given that:-
The density of the solid Ag = 10.5 g/cm³
Molar mass of silver = 107.8682 g/mol
So, Moles present per cm³ of Ag = 
=0.0973 mol/cm³
Also, 1 mole = 
atoms.
So,
Atoms present per cm³ of Ag = 
Thus, answer = 
In FCC, the number of atoms in the unit cell = 4 unit cells
So,
Unit cells which are present per cubic centimeter of Ag = 
<u>Unit cells which are present per cubic centimeter of Ag = </u>
(b)
The reciprocal of the unit cell/cm³ is the volume of the unit cell.
So, 
<u>Volume = </u>
(c)
Also, Volume = 
Thus, edge length = 
= 
<u>Edge length = </u>
