Answer: False
Explanation:
4C2H6 + 7O2 --> 6H2O + 4CO2
8 Carbons on the reactant side, but 4 Carbons on the Product
24 Hydrogens on Reactant, 12 H on product
But Oxygen is balanced, 14 on each side
Answer/Explanation
Characteristics of Life Present in Viruses:
- has a defined boundary - viruses are made up simply of genetic material surrounded by a<u> protein capsid </u>and sometimes a lipid membrane
Characteristics of Life Absent in Viruses:
- made up of one or more cells - one of the main arguments for why viruses are not living is that they are <u>not cellular</u>
- uses energy - this is a tricky one. They don't use or produce their own energy. However, in order to reproduce they do hijack the host cells and <u>steal energy</u> from them in order to reproduce
- exhibits growth and development - although viruses do <u>reproduce</u>, the individual viral particles do not exhibit growth or development
- possess internal organisation - other than the fact they ahve genetic material, the inside of a virus does not contain internal organization like a cytosol, instead conssiting of the bare minimum amount of proteins to survive
- eliminates waste - since they do not have their own metabolism, they have no waste to eliminate
Answer:
You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid.
Explanation:
Answer:
0.17%
Explanation:
With the equation:
2Cr2O7 2- + C2H5OH + H2O --> 4Cr3+ + 2CO2 + 11H2O
We can assume that every mole of ethanol needs 2 moles of Dichromate to react.
So if in 1L we have 0.05961 moles of dichromate we can discover how many moles we have in 35.46mL
1000 mL - 0.05962 moles
35.46 mL - x
x = 
x = 2,11* 10^-3 moles
As we said earlier, 1 mole of ethanol needs 2 mole of dichromate, so in the solution we have 1,055*10^-3 moles of ethanol. We can discover the mass of ethanol present in the solution.
1 mole - 46g
1.055*10^-3 - y
y = 46 * 1.055*10^-3
y = 0.048 g
To discover the percent of alchol we can use a simple relation
28 g - 100%
0.048 - z
z = 
z = 0.17%
