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katovenus [111]
2 years ago
10

Calculate the mass of 12.3 moles of MgSO4.​

Chemistry
2 answers:
Afina-wow [57]2 years ago
8 0

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

belka [17]2 years ago
3 0
614 034 kg hope it help out
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