1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sweet-ann [11.9K]
3 years ago
6

A 60.0 g block of iron that has an initial temperature of 250. °C and 60.0 g bloc of gold that has an initial temperature of 45.

0 °C are brought into contact with one another. Assuming no heat is lost to the surroundings, what will be the temperature when the two metals reach thermal equilibrium? The specific heat capacity of iron = 0.449 J/g•°C and gold = 0.128 J/g•°C.
Chemistry
1 answer:
Maslowich3 years ago
5 0

Answer:

The final temperature at the equilibrium is 204.6 °C

Explanation:

Step 1: Data given

Mass of iron = 60.0 grams

Initial temperature = 250 °C

Mass of gold = 60.0 grams

Initial temperature of gold = 45.0 °C

The specific heat capacity of iron = 0.449 J/g•°C

The specific heat capacity of gold = 0.128 J/g•°C.

Step 2: Calculate the final temperature at the equilibrium

Heat lost = Heat gained

Qlost = -Qgained

Qiron = -Qgold

Q=m*c*ΔT

m(iron) * c(iron) *ΔT(iron) = -m(gold) * c(gold) *ΔT(gold)

⇒with m(iron) = the mass of iron = 60.0 grams

⇒with c(iron) = the specific heat of iron = 0.449 J/g°C

⇒with ΔT(iron)= the change of temperature of iron = T2 - T1 = T2 - 250.0°C

⇒with m(gold) = the mass of gold= 60.0 grams

⇒with c(gold) = the specific heat of gold = 0.128 J/g°C

⇒with ΔT(gold) = the change of temperature of gold = T2 - 45.0 °C

60.0 *0.449 * (T2 - 250.0) = -60.0 * 0.128 * (T2 - 45.0 )

26.94 * (T2 - 250.0) = -7.68 * (T2 - 45.0)

26.94T2 - 6735 = -7.68T2 + 345.6

34.62T2 = 7080.6

T2 = 204.5 °C

The final temperature at the equilibrium is 204.6 °C

You might be interested in
What evidence is there that all state of matter have mass
katovenus [111]

Answer:

Matter is the "stuff" that makes up the universe everything that takes up space and has mass is matter.

All matter is made up of atoms, which are in turn made up of protons, neutrons and electrons

8 0
3 years ago
Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from
aliina [53]

Answer:

1.82 L

Explanation:

We are given the following information;

  • Initial volume as 2.0 L
  • Initial temperature as 60.0°C
  • New volume as 30.0 °C

We are required to determine the new volume;

From Charles's law;

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where, V_1 and V_2 are initial and new volume respectively, while T_1 and T_2 are initial and new temperatures respectively;

T_1= 333 K

T_2=303K

V_1 =2.0L

Rearranging the formula;

V_2=\frac{V_1T_2}{T_1}

    = \frac{(2.0L)(303K)}{333K} \\=1.820 L

Therefore, the new volume that would be occupied by the gas is 1.82 L

7 0
3 years ago
The oxygen atom is smaller than the sulfur atom because _____(1) the outer electrons of oxygen are more effectively screened fro
Romashka [77]

Answer: Option (2) is the correct answer.

Explanation:

Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.

As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.

Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.

Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.

Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.

3 0
3 years ago
Moles to mass<br> HELP PLEASE <br> 15 pts
MariettaO [177]

Explanation:

nose amigo, la verdad yo también tengo dificultades escolares muchísimas gracias, Dios te bendiga en otro idioma por cierto mi anime favorito es cowboy beboop

4 0
2 years ago
Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample
k0ka [10]

Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

<u>Step 1:</u> Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

<u>Step 2:</u> The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

<u>Step 3:</u> Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

<u>Step 4:</u> Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

<u>Step 5</u>: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M

6 0
3 years ago
Other questions:
  • Among teenagers, what is the most commonly used substance?
    9·1 answer
  • Which method would be the best to use in order to separate a mixture of water and rubbing alcohol?
    11·1 answer
  • Which part of the water cycle would follow step C in the diagram shown?
    14·1 answer
  • Which element will have the greatest attraction for the calcium electrons?
    13·1 answer
  • Consider this reaction: Zn(s) + 2HCl(aq) ZnCl2(aq) + H2(g). Which change could decrease the rate of production of ZnCl2?
    7·2 answers
  • The rate of effusion of a particular gas was measured and found to be 24.0 mL/min. Under the same conditions, the rate of effusi
    5·1 answer
  • When 2.35 g of potassium reacts with excess water, what mass of hydrogen gas is formed?
    14·1 answer
  • Which half-reaction correctly represents reduction?
    8·1 answer
  • CHECK MY RECENT QUESTION HELP ME ASAP
    11·1 answer
  • Ok so N2+O2=2NO and my delta h is 180.5 kJ I need to know. If I react 10 g of nitrous gas with excess oxygen how many grams of N
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!