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vladimir2022 [97]
3 years ago
6

0.2(10-5c)=5c-16 halp

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

c= 3

Step-by-step explanation:

0.2(10 -5c)= 5c -16

<em>Expand</em><em>:</em>

0.2(10) +0.2(-5c)= 5c -16

2 -c= 5c -16

<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

5c +c= 2 +16

<em>Simplify</em><em>:</em>

6c= 18

<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

c= 18 ÷6

c= 3

kodGreya [7K]3 years ago
3 0

Answer:

c = 3

Step-by-step explanation:

(1): "0.2" was replaced by "(2/10)".

<u><em>Rearrange:</em></u>

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

               (2/10)*(10-5*c)-(5*c-16)=0

<em><u>Simplify:</u></em>

                 1

Simplify   —

                 5

<u><em>Equation at the end of step  1 : </em></u>

  1                  

 (— • (10 - 5c)) -  (5c - 16)  = 0  

  5                

<u><em>STEP  2 : </em></u>

<u><em>STEP  3 : </em></u>

<u><em>Pulling out like terms </em></u>

3.1     Pull out like factors :

  10 - 5c  =   -5 • (c - 2)

<em><u>Equation at the end of step  3 : </u></em>

 (2 - c) -  (5c - 16)  = 0

<u><em>STEP  4 : </em></u>

<u><em>STEP  5 : </em></u>

<u><em>Pulling out like terms </em></u>

5.1     Pull out like factors :

  18 - 6c  =   -6 • (c - 3)  

<u><em>Equation at the end of step  5 : </em></u>

 -6 • (c - 3)  = 0  

<u><em>STEP  6 : </em></u>

<u><em>Equations which are never true </em></u>

6.1      Solve :    -6   =  0

<u><em>This equation has no solution. </em></u>

<u><em>A a non-zero constant never equals zero.  (The one above)</em></u>

<u><em>Solving a Single Variable Equation: </em></u>

6.2      Solve  :    c-3 = 0  

Add  3  to both sides of the equation :  

             <u><em>Therefore the answer is:</em></u><em>   </em>     <u><em>c = 3</em></u>

<u><em></em></u>

<u><em>HOPE THIS HELPS!</em></u>

<u><em>PLEASE MARK BRAINLIEST IF YOU LEARNED FROM THIS! :)</em></u>

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Which statement shows how the product of (x + 7)2 demonstrates the closure property of multiplication?
Illusion [34]

<h3>(x + 7)² = x² + 14x + 49</h3>

The true statement that show the closure property of multiplication :

<h3>a.  x² + 14x + 49 is a polynomial</h3>

\texttt{ }

<h3>Further explanation</h3>

<em>If equation ax³ + bx² + cx + d = 0 has roots x₁ , x₂ , and x₃ then</em>

x_1 + x_2 + x_3 = - \frac{b}{a}

x_1 x_2 + x_1 x_3 + x_2 x_3 = \frac{c}{a}

x_1 x_2 x_3 = - \frac{d}{a}

Let us now tackle the problem!

\texttt{ }

This problem is about Polynomial.

(x + 7)^2 = (x + 7)(x + 7)

(x + 7)^2 = x^2 + 7x + 7x + 7(7)

(x + 7)^2 = x^2 + 14x + 49

x^2 + 14x + 49 is a polynomial.

x + 7 is polynomial.

It demonstrates the closure property of multiplication.

\texttt{ }

<h3>Conclusion:</h3>

<em>The true statement that show how the product of (x + 7)² demonstrates the closure property of multiplication:</em>

<h3>a.  x² + 14x + 49 is a polynomial</h3>

\texttt{ }

<h3>Learn more</h3>
  • Solving Quadratic Equations by Factoring : brainly.com/question/12182022
  • Determine the Discriminant : brainly.com/question/4600943
  • Formula of Quadratic Equations : brainly.com/question/3776858

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Polynomial

\texttt{ }

Keywords: Quadratic , Equation , Discriminant , Real , Number

#LearnWithBrainly

7 0
3 years ago
Read 2 more answers
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