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3 years ago

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Leslie is buying potatoes at a store. This graph shows the relationship between the number of pounds of potatoes she buys and th

e total cost
Based on the graph, what is the unit cost, in dollars, of the potatoes?

2 answers:

Goryan [66]3 years ago

7 0

Answer: It’s 0.75 is my best guess. Let me know if that wrong

Step-by-step explanation:

pishuonlain [190]3 years ago

7 0

Answer: It’s 0.75 is my best guess. Let me know if that wronger:

Step-by-step explanation:

You might be interested in

Circles and segments create the many relationships addressed in the theorems throughout this unit. Use those theorems and the in

ohaa [14]

In your questions where the segment and circles create many relationship addressed in the theorem throughout this unit. So the following are the answers:
b.KI=5
c. EP = 2
e. CJ = 6
f.FH=14.4
g.AE=8.75

I hope you are satisfied with my answer

8 0

3 years ago

Solve for x in the equation 2x^2+3x-7=x^2+5x+39

Shalnov [3]

Hey there, hope I can help!

$\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}$
$2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)$

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
$x^2-2x-46=0$

Lets use the quadratic formula now
$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$
$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}$

$\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \ \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}$

Multiply the numbers 2 * 1 = 2
$\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}$

$2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \ \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \ \left(-2\right)^2=2^2, 2^2 = 4$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \ \sqrt{4+184} \ \textgreater \ \sqrt{188} \ \textgreater \ 2 + \sqrt{188}$
$\frac{2+\sqrt{188}}{2} \ \textgreater \ Prime\;factorize\;188 \ \textgreater \ 2^2\cdot \:47 \ \textgreater \ \sqrt{2^2\cdot \:47}$

$\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \ \sqrt{47}\sqrt{2^2}$

$\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \ \sqrt{2^2}=2 \ \textgreater \ 2\sqrt{47} \ \textgreater \ \frac{2+2\sqrt{47}}{2}$

$Factor\;2+2\sqrt{47} \ \textgreater \ Rewrite\;as\;1\cdot \:2+2\sqrt{47}$
$\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \ 2\left(1+\sqrt{47}\right) \ \textgreater \ \frac{2\left(1+\sqrt{47}\right)}{2}$

$\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ 1+\sqrt{47}$

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

$\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \ \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}$

$\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}$

$2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \ 2-\sqrt{188} \ \textgreater \ \frac{2-\sqrt{188}}{2}$

$\sqrt{188} = 2\sqrt{47} \ \textgreater \ \frac{2-2\sqrt{47}}{2}$

$2-2\sqrt{47} \ \textgreater \ 2\left(1-\sqrt{47}\right) \ \textgreater \ \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \ 1-\sqrt{47}$

Therefore our final solutions are
$x=1+\sqrt{47},\:x=1-\sqrt{47}$

Hope this helps!

8 0

3 years ago

Read 2 more answers

If two thirds of a number decreased by 20 is 40, what is the number

oee [108]

Answer:

The unknown number is 90

Step-by-step explanation:

This question requires a good understanding so as to interprets it well

And always ensure that all symbols used in representation are well stated so as to help the examiner or anyone who will mark it to understand better

So back to the question,let the unknown number be x

And two thirds of the unknown number is 2/3x

2/3x was decreased by 20 which can be written as 2/3x-20

And this decrease gives 40

That's,2/3x-20=40

Then go ahead to solve the question

Start by finding the LCM and the LCM is 3

2x-60/3=40

Cross multiply

2x-60=40×3

2x-60=120

Collect like terms by adding 60 to both sides

2x=180

Divide both sides by 2

x=90

Therefore the final answer is 90

8 0

3 years ago

How do you do number 25? At the bottom.

Ivanshal [37]

<u>Answer-</u>

<em>The printer used </em><em>642 digits</em><em> to print all the pages in the book.</em>

<u>Solution-</u>

There are 250 pages numbered starting from 1 to 250.

The total number of digits would be the sum of digits of all single digits from 1 to 9, all double digits number from 10 to 99, and all triple digits number from 100 to 250.

There are 9 single digit numbers from 0 to 9, 90 double digit numbers from 10 to 99, and 151 triple digit numbers from 100 to 250.

So,

$\text{Total digits}=(1\times 9)+(2\times 90)+(3\times 151)\\\\=9+180+453\\\\=642$

Therefore, the printer used 642 digits to print all the pages in the book.

3 0

4 years ago

Can someone solve this for me?

Naya [18.7K]

Answer:

-1/2

Step-by-step explanation:

Slope is defined as change in x/change in y.

The x changed by 1/8-(-1/4)=3/8 and the y changed by -4-(-1/4)=(-3/4).

Now, divide the 2 fractions:

(-3/4)/3/8 = -3/4*8/3 = -4/8 = -1/2

5 0

3 years ago