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NARA [144]
3 years ago
9

Which expression uses the distributive property to represent the sum of 39 + 27

Mathematics
1 answer:
aalyn [17]3 years ago
3 0

Answer:

The expression that uses the distributive property to represent the sum of 39 + 27 is 3(13 + 9)

Step-by-step explanation:

Given

Expression: 39 + 27

Required

Express using the distributive property

The distributive property is represented in the form a(b + c)

So, we can say that the meaning to the question is that the given expression should be represented in the form a(b+c)

Equate these two expressions, we have

a(b+c) = 39 + 27

Factorize the expression on the left hand side

a(b+c) = 3(\frac{39}{3} + \frac{27}{3})

Simplify fraction

a(b+c) = 3(13 + 9)

Compare expression on left hand side with the expression on the right hand side.

Since, they have the same format, then we've arrived at the answer.

Hence, the expression that uses the distributive property to represent the sum of 39 + 27 is 3(13 + 9)

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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be . Saul asks Jasmine
Amiraneli [1.4K]

The question is incomplete. The compete question is :

Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?

Solution :

The inter quartile range is being measured as : 3rd quartile - 1st quartile

The 1st quartile = 25% mark

The 3rd quartile = 75% mark

The data set as given in the question is :

25, 30, 50, 50, 50, 50, 56, n, 250

Therefore, the total number of the sample = 9

And the median is = 50

The median separates the given data sets into two equal halves-- that is the upper half and the lower half.

Let the middle of a lower half is the 1st quartile be $Q_1$

And the middle of a 2nd half is the 3rd quartile be $Q_3$

∴ $Q_1=\frac{30+50}{2}$

        $=40$

  $Q_3=\frac{56+n}{2}$

Now for the IQR of the data set to be equal to $27$,

$\frac{56+n}{2}-40=27$

$\frac{56+n}{2}=27+40$

$\frac{56+n}{2}=67$

$56 +n=134$

$n=134-56$

$n=78$

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John bought 3 pineapples and 2 watermelons for $8.50. Sue bought 2 pineapples and 4 watermelons for $13.00. Write and show a sys
AleksAgata [21]
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If the quantity of watermelon is odd, then the total cost value of pineapple should end with 3 and this is not possible when the cost of pineapple is ₹7.

So let's come to conclusion that the count(quantity) of watermelon should be any one of 0, 2, 4, 6.

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If count of watermelon is 0: It will cost you ₹0 and for remaining ₹38, we can buy 5 pineapple with ₹3 being not utilised. So 5 pineapple is also not possible.

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