Which dog eats the most food per week

Solve the system by substitution

Andru [333]

A solution on the photos

4 0

3 years ago

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Let f(x)=x2−8x+19 . What is the minimum value of the function? Enter your answer in the box.

ella [17]

The minimum value is 3.

6 0

3 years ago

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The first four terms of a sequence are shown below: 9, 5, 1, â’3 Which of the following functions best defines this sequence? f(

matrenka [14]

The function that best defines this arithmetic sequence is:

$f(n) = f(n - 1) - 4, f(1) = 9$

<h3>What is an arithmetic sequence?</h3>

In an <em>arithmetic sequence,</em> the <u>difference between consecutive terms is always the same</u>, called common difference d.

The recursive function that defines the sequence is:

$f(n) = f(n - 1) + d$

$f(1) = f_0$

In which $f_0$ is the first term.

In this problem, the sequence is: {9, 5, 1, -3}

Each term is the previous term subtracted by 4, hence $d = -4$ .

The first term is 9, hence $f_0 = 9$ .

Hence, the function is:

$f(n) = f(n - 1) - 4, f(1) = 9$

You can learn more about arithmetic sequences at brainly.com/question/6561461

5 0

2 years ago

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Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim

andreev551 [17]

Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0

3 years ago

Investigate the difference between compounding annually and simple interest

Gennadij [26K]

Step-by-step explanation:

Simple interest formula

$A = P (1 + rt)$

Compound interest formula

$A = P(1 + \frac{r}{n})^{nt}$

a.

$A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125$

Simple interest is $125

b

. $A = 5000 (1 + \frac{0.025}{1})^{1*1} \\A=5000(1.025)\\A= 5125$

Compound interest is $125

c. the result for both a and b are the same

d.

$A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375$

the simple interest is $375

e

. $A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385$

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

$A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600$

the simple interest is $600

h.

$A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869$

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

6 0

3 years ago