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Nezavi [6.7K]
3 years ago
14

2a + 3b = 5 b = a - 5 What is a and b?

Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0
2a + 3(a-5) = 5, 2a + 3a+15=5, 5a=-10, a=-2, b= (-2) -5, b=-7...a=-2, b=-7
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Justin has a credit card with a limit of $1,000 and an introductory APR of 0% for six months. After that the, APR for purchases
yuradex [85]
Given:
APR for first six months = 0%
APR for purchases after the 1st six months = 22.9%
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Obtaining $350 from an ATM using his credit card is a form of Cash Advances. So, the APR for this transaction is 24.9% Choice A.
4 0
3 years ago
How to do this plz tell​
VARVARA [1.3K]
3. = 6/12
6. = 4/6
9. = 8/12
12. = 9/12
15. = 9/9
18. = 4/6
Hope this helps !
6 0
3 years ago
Read 2 more answers
Select the correct answer. which data set is the farthest from a normal distribution? a. 2, 3, 3, 4, 4, 4, 5, 5, 6 b. 3, 4, 5, 6
tigry1 [53]

The answer choice which is the farthest from a normal distribution is; Choice E; 2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10.

<h3>Which data set is farthest from a normal distribution?</h3>

A normal distribution, is a data set which when graphed must follow a bell-shaped symmetrical curve centered around the mean. Additionally, such distribution must adhere to the empirical rule that indicates the percentage of the data set that falls within (plus or minus) 1, 2 and 3 standard deviations of the mean.

On this note, upon evaluation of the data sets, it follows that answer choice E represents the data set that's most farthest from a normal distribution.

Read more on normal distribution;

brainly.com/question/26678388

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4 0
2 years ago
Which is a solution for the equation 3x + 13 = 73?
sweet [91]

Answer:

x=20

Step-by-step explanation:

73-13=60

60÷3=20

7 0
3 years ago
Read 2 more answers
I need some help with this calculus 1 implicit diffrention problem?
katen-ka-za [31]

Answer:

y" = -24 / y³

Step-by-step explanation:

6x² + y² = 4

Take the derivative of both sides with respect to x.

12x + 2y y' = 0

Again, take the derivative of both sides with respect to x.

12 + 2y y" + y' (2y') = 0

12 + 2y y" + 2(y')² = 0

Solve for y' in the first equation.

2y y' = -12x

y' = -6x/y

Substitute and solve for y":

12 + 2y y" + 2(-6x/y)² = 0

12 + 2y y" + 2(36x²/y²) = 0

12 + 2y y" + 72x²/y² = 0

6y² + y³ y" + 36x² = 0

y³ y" = -36x² − 6y²

y" = (-36x² − 6y²) / y³

Solve for y² in the original equation and substitute:

y² = 4 − 6x²

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y" = (-36x² − 24 + 36x²) / y³

y" = -24 / y³

7 0
3 years ago
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