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Nezavi [6.7K]
3 years ago
14

2a + 3b = 5 b = a - 5 What is a and b?

Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0
2a + 3(a-5) = 5, 2a + 3a+15=5, 5a=-10, a=-2, b= (-2) -5, b=-7...a=-2, b=-7
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The equatorial radius of the planet Jupiter is measured 40 times by a process that is practically free of bias. These measuremen
Nina [5.8K]

Answer:

The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.

Step-by-step explanation:

Sample size of 30 or larger, so we can use the normal distribution to find the confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.93}{2} = 0.035

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.81*\frac{28}{\sqrt{40}} = 8

The lower end of the interval is the sample mean subtracted by M. So it is 71492 - 8 = 71484 km.

The upper end of the interval is the sample mean added to M. So it is 71492 + 8 = 71500 km.

The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.

8 0
3 years ago
What is f(-3) for the function f(a)=-2a2-5a+4?
posledela

Answer:

-25

Step-by-step explanation:

2a² - 5a + 4, for f(-3)

2(-3)² -5(-3)+4

2*(-27)+15+4

-54+19

= -25

4 0
3 years ago
Evaluate 2times 8+5-18divided by3
Taya2010 [7]

Answer:

Step-by-step explanation:

PEMDAS (order of operations)

2 times 8=16

18/3= 6

16+5-6=15

4 0
4 years ago
Work out the value of <img src="https://tex.z-dn.net/?f=2%5E%7B3%7D%20%2B%205%5E%7B2%7D" id="TexFormula1" title="2^{3} + 5^{2}"
Luden [163]

Answer:

33

Step-by-step explanation:

2³=8

5²=25

8+25=33.

so, 2³+5²=33

4 0
3 years ago
Read 2 more answers
Y=x^2-4x+5 to factored form
harina [27]

Answer:

(2+i)(2-i)

Step-by-step explanation:

7 0
3 years ago
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