The two expressions are both rational numbers- they are ending, whole and have no decimals.
Answer:
same
Step-by-step explanation:
Answer: 2
Step-by-step explanation:
Here is the solution...
1) ![\sqrt[3]{135} \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%5C%5C)
Solution
We can rewrite ![\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here, ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%3D%203)
Now substitute the value, we get
![\sqrt[3]{135} = 3 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%203%20%5Csqrt%5B3%5D%7B5%7D)
The answer is ![3\sqrt[3]{5}](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7B5%7D)
2) ![-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}](https://tex.z-dn.net/?f=-5%5Csqrt%5B3%5D%7B40%7D%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3ESolution%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D-5%5Csqrt%5B3%5D%7B40%7D%20%3D%20-5%5Csqrt%5B3%5D%7B8%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here ![\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B3%7D%20%7D%20%3D%202%5C%5C)
Therefore, we get ![-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}](https://tex.z-dn.net/?f=-5%2A2%5Csqrt%5B3%5D%7B5%7D%20%3D%20-10%20%5Csqrt%5B3%5D%7B5%7D)
The answer is-10 \sqrt[3]{5}[/tex]
2) ![2\sqrt[3]{5} * 4\sqrt[3]{8}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B5%7D%20%2A%204%5Csqrt%5B3%5D%7B8%7D)
Solution
![\sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%202)
Now plug in the above in the given expression, we get
{2*4*2 = 16]
The answer is ![16\sqrt[3]{5}](https://tex.z-dn.net/?f=16%5Csqrt%5B3%5D%7B5%7D)
1/6 of the shingles/ 2 stacks= 1/12 of the shingles/stack.
There will be 1/12 of the shingles in each stack~