All categories

3 years ago

Solve 5x2 = 180 algebraically.

Mathematics

2 answers:

IRISSAK [1]3 years ago

5 0

Answer:

x = ±6

Step-by-step explanation:

5x^2 = 180

Divide each side by 5

5x^2/ 5 = 180/5

x^2 = 36

Take the square root of each side

sqrt(x^2) = ± sqrt(36)

x = ±6

anastassius [24]3 years ago

5 0

Answer: x = 6 or x = -6

Step-by-step explanation: First, isolate the x squared by dividing both sides by 5 to get x² = 36. Now, since x is squared, we simply take the square root of both sides of the equation to get x by itself.

When we take the square root of both sides of an equation,

we must always make sure to use plus or minus!

So x = ±5 and you can write your answer as the solution set {6, -6}.

You might be interested in

Jessica works between 12h and 18h per week at her part-time job. She earns $9.25 per hour. The function p(h) = 9.25h models the

Tpy6a [65]

D. All real numbers between 111 and 166.5 inclusive.

3 0

4 years ago

Plz help me tyyysmmm

ch4aika [34]

Answer:

$60 \sqrt{2}$

7 0

3 years ago

Helllohello help please if you want -

IRINA_888 [86]

Hey Hey! It's me again!

Answer:

The variable u divided by the variable x.

8 0

3 years ago

Please answer 25 points!

Alekssandra [29.7K]

Answer:

-3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with

saw5 [17]

Answer:

b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

The sum of angles in a triangle is 180°, no more, no less.
The sum of the lengths of the two shortest sides exceeds the longest side.
When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

Additional comment

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

The congruence postulates for triangles are ...

SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define a singular triangle. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the longest specified side, regardless of that angle's measure. However, when the angle is opposite the shortest specified side, the above-described ratio restriction holds. If the sine of the angle is less than the ratio of sides, then two possible triangles are specified.

4 0

3 years ago