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guapka [62]
3 years ago
10

Solve 5x2 = 180 algebraically.

Mathematics
2 answers:
IRISSAK [1]3 years ago
5 0

Answer:

x = ±6

Step-by-step explanation:

5x^2 = 180

Divide each side by 5

5x^2/ 5 = 180/5

x^2 = 36

Take the square root of each side

sqrt(x^2) = ± sqrt(36)

x = ±6

anastassius [24]3 years ago
5 0

Answer: x = 6 or x = -6

Step-by-step explanation: First, isolate the x squared by dividing both sides by 5 to get x² = 36. Now, since x is squared, we simply take the square root of both sides of the equation to get x by itself.

When we take the square root of both sides of an equation,

we must always make sure to use plus or minus!

So x = ±5 and you can write your answer as the solution set {6, -6}.

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Assume that AABC= APQR. Which of the following congruence statements
Burka [1]

Answer:

Options B, D, E

Step-by-step explanation:

If triangle ABC and triangle PQR are congruent,

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∠C ≅ ∠R

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8 0
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solong [7]
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olga55 [171]

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3 0
3 years ago
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agasfer [191]

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7 0
3 years ago
Read 2 more answers
Factorise: 8x^3 + 27y^3 + 36x^2y + 54xy^2
Free_Kalibri [48]

Answer:

=(2x−3y)(2x−3y)(2x−3y)

Step-by-step explanation:

8x  

3

−27y  

3

−36x  

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y+54xy  

2

 

=(2x)  

3

−(3y)  

3

−3×(2x)  

2

×3y+3×2x×(3y)  

2

 

Using,(a−b)  

3

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−b  

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−3a  

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=(2x−3y)  

3

 

=(2x−3y)(2x−3y)(2x−3y)

5 0
2 years ago
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