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Nonamiya [84]
2 years ago
14

What is the volume of a right circular cone with a radius of 3 units and a height of 6 units?​ pleas help asap

Mathematics
1 answer:
a_sh-v [17]2 years ago
3 0

Answer:

18 units

Step-by-step explanation:

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Evan’s family drove to a theme park for vacation.
zhuklara [117]

Answer:

They drove 150 miles on the third day

They drove 50 miles per hour so if you multiply that by 3 (since they drove 3 hours on the third day) you would get 150 miles.

5 0
2 years ago
A certain alloy contains 5.25% copper. How much copper is there I a piece weighing 200 pounds?
kykrilka [37]
Find 5.25% of 200
remember
1% of 100=1
therefor
1% of 200=2
just remove the decimal and double it (for this special case of finding percent of 200)

5.25% of 200=5.25 times 2=10.5
answer is 10.5 pounds of copper
(the legit way is 0.0525 times 200=10.5 pound)


10.5lb is answer
4 0
3 years ago
Read 2 more answers
Ana uses the greatest common factor and the distributive property to rewrite this sum:
creativ13 [48]
Your equation or notation would be:   12(6+5)
8 0
2 years ago
John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S
Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work =20\ km/hr

Sheri's commute to work  =500\ m/min

1.61\ km = 1\ mile

John's commute to work in miles per hour = \frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr

Sheri's commute to work in miles per hour =\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr

We can see that Sheri has a faster commute.

Difference between the rates =18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr

∴ Sheri has the faster commute by 6.2 miles/hr.

3 0
3 years ago
What is the value of the contangent of
MariettaO [177]

Given:

In triangle WXY, m\angle W=90^\circ, WX=8, XY=17, WY=15.

To find:

The Cotangent of \angle X.

Solution:

In a right angle triangle,

\cot \theta=\dfrac{Base}{Perpendicular}

It can be written as:

\cot \theta=\dfrac{Adjacent}{Opposite}

For triangle WXY,

\cot (\angle X)=\dfrac{WX}{WY}

\cot (\angle X)=\dfrac{8}{15}

Therefore, the Cotangent of \angle X is \dfrac{8}{15}.

6 0
3 years ago
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