<img src="https://tex.z-dn.net/?f=5x-6%3D3x-8" id="TexFormula1" title="5x-6=3x-8" alt="5x-6=3x-8" align="absmiddle" class="latex

All categories

xxMikexx [17]

3 years ago

-formula">

Mathematics

2 answers:

Nata [24]3 years ago

7 0

X = -1

Worked it out for ya :)

julsineya [31]3 years ago

6 0

$5x-6=3x-8$

$5x-6+6=3x-8+6$

$5x=3x-2$

$5x-3x=3x-2-3x$

$2x=-2$

$\frac{2x}{2}=\frac{-2}{2}$

$x=-1$

You might be interested in

My salary is £28,860 per year. What is my hourly rate of pay if I work 37 hours a week

Nostrana [21]

Answer:

pay rate £7.80

Step-by-step explanation:

28860 divide by 37 = 780

780 divided by 100 = 7.80

4 0

3 years ago

Plot the points in the coordinate plane. Then find the perimeter and area of the polygon.

anyanavicka [17]

Answer:

The answer to your question is below

Step-by-step explanation:

See the graph below

Process

1.- Find the distance from A to B, B to C, C to D, A to D

Formula

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}$

d AB = $\sqrt{(1 + 3)^{2} + (6 - 5)^{2}} = \sqrt{17}$

dBC = $\sqrt{(-2 -6)^{2} + (3 - 1)^{2}} = \sqrt{68}$

dCD = $\sqrt{(-1 - 3)^{2} + (-3 +2)^{2}} = \sqrt{17}$

dAD = $\sqrt{(-1 + 3)^{2} + (-3 - 5)^{2}} = \sqrt{68}$

2.- Find the perimeter

Perimeter = 2 $\sqrt{17} + 2\sqrt{68}$ = $6\sqrt{17}$ u

3.- Find the area

Area = $\sqrt{17} x \sqrt{68}$

Area = $\sqrt{17x68} = \sqrt{1156} = 34 u^{2}$

7 0

3 years ago

Madeline needs to find the slope of the line that passes through the points (9, 12) and (7, 4). She sets up the following work:

Over [174]

Answer:

Step-by-step explanation:

She has everything correct but one thing. In order to have her answer correct, she must put the 9 in front of the 7 because the bigger number needs to go in front.

4 0

3 years ago

A boy flying a kite lets out 300 feet of string, which makes an angle of 38o with the ground. Assuming that the string is straig

Greeley [361]

Answer:

The answer is 184.7 ft

Step-by-step explanation:

You need to find the distance from kite to ground

sin38°/1 = x/300

x = 300 · sin 38

Therefore your answer is 184.7

This is the best way I could explain it....Hope this helps:)

4 0

3 years ago

The equation x^2+ (k - 3)x + (3 - 2k) = 0, where k is a constant, has two distinct real roots.

Lisa [10]

Step-by-step explanation:

For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,

b^2 - 4ac must be positive.

b^2 - 4ac > 0

(k - 3)^2 - 4(3 - 2k) > 0

k^2 - 6k + 9 - 12 + 8k > 0

k^2 + 2k - 3 > 0

4 0

3 years ago