Answer:
He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24
Step-by-step explanation:
First we have to calculate the least common multiple (LCM) of 24 and 30
We will calculate the LCM of 24 and 30 by prime factorization method
24 = 2*2*2*3 = 
30 = 2*3*5 = 
LCM = 
LCM = 120
So number of hamburger buns = 120
Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30
<span>Frieda's weight is 1 Standard Deviation above the meanwhile her height is less than 1 Standard Deviation away from the mean. This means her height is closer to the mean than her weight.
As a result, we would say that her weight is definitely more unusual than her height because her weight is more standard deviations away from the mean.
Therefore,
</span><span>in relative terms, it is correct to say that:</span> Frieda's height is more unusual than her weight.
Answer:
For the first box, the answer is 3.
For the second box, the answer is -1.
For the third box, the answer is 0.
I hope this helped!
You must factoring the number 192, you will get 192=2^6*3, so you have square root(2^6*3)=2^(6/2)*root(3) applying enhancing property.
Solve the exponent and you get =2^3*root(3)= 8*root(3)
For this case we have the following system of equations:

We multiply the first equation by -4:

We have the following equivalent system of equations:

We add the equations:

We find the value of the variable "x":

Thus, the solution of the system is:

See the graphic in the attached image
ANswer:

See the graphic in the attached image