Answer:
Volume of slice is 40 in³
Volume of the remaining cake is 197.014 in³
Step-by-step explanation:
hope this helps!!
brainliest please?
It will be 5 years and 5 months.
Answer:
Yes it is, because...
Step-by-step explanation:
This is an inequality, so you can treat it as an algebraic expression.
The first step is to multiple both sides by 2, to get rid of the 2 on the left side.
Your equation will now look like this:
y >= 2y - 22
The next step is to get all the y variables to one side, now that its a lot more simplified. Subtract 2y from both sides to get:
-y >= -22
Finally, cancel out the negative on both sides of the equation to get the y as a positive y, all by itself. This will get you:
y <= 22
REMINDER: when you divide by a negative number, such as in this case dividing by -1 on both sides, the inequality sign will flip!
y = 18 works because it is less than 22. (:
<u>These 2 equations has </u><u>no solution</u><u> and the equations are </u><u>independent</u><u> </u><u>of each other.</u>
What is liner equation with two variable?
- An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
- For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.
-10x² -10y² = -300 ----a
5x² + 5y² = 150 ---- b
While trying to solve this,
We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.
10x² + 10y² = 300 ----c
-10x² -10y² = -300 ---a
<u>Everything cutoff, we will </u><u>get 0</u><u>, and there is no solution to these equations.</u>
Learn more about liner equation with two variable brainly.com/question/16933755
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We will use double angle identities:
cos (5x ) = sin (10x )
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0 or : 1 - 2 sin (5 x) = 0
5 x = π/2 +kπ, k∈Z sin (5 x) = 1/2
x1 = π/10 + kπ/5 5 x = π/6+2kπ , k∈ Z
5 x = 5π/6 +2kπ , k∈ Z
x 2 = π/30 +2kπ/5
x 3 = π/9 + 2kπ/5
