Answer:
F₃ = -151 N i + 96 N j
Explanation:
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
Forces acting on the object
F₁= 3.0 N i + 16.0 N j
F₂ = -12.0 N i+ 8.0 N j
F₃ = F₃x N i +F₃ y N j
x component of the net force on the object
Fx=F₁x+F₂x+F₃ x
Fx = 3.0 N-12.0 N +F₃x
Fx = F₃x - 9 N
y component of the net force on the object
Fy=F₁y+F₂y+F₃ y
Fy =16.0 N+ 8.0 N +F₃y
Fy = F₃y + 24 N
Newton's second law to the object:
a = -8 m/s² i + 6.0 m/s² j
∑Fx = m*ax m=20 kg , ax = -8 m/s²
F₃x - 9 = 20 *(-8)
F₃x = -160+9
F₃x = -151 N
∑Fy = m*ay m=20 kg , ay = 6 m/s²
F₃y + 24 =20*( 6 )
F₃y =120 - 24
F₃y = 96 N
F₃ = -151 N i + 96 N j
You should calculate 40 kg and the radius 3mm.
Are there supposed to be multiple choices for this question?
Answer: false
Explanation:
While kilograms are the unit used to measure body mass, the device used is a scale.
Hope it helps :)
Answer:
Displacement from the starting position is 1224m
Explanation:
The object is moving at 120 meters per second, it does this for 10.2 seconds. Use multiplication to find the answer.
