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ArbitrLikvidat [17]
2 years ago
6

Now, find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 11. Then div

ide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C. What is the concentration of H+ ions at a pH = 11? mol/L What is the concentration of OH– ions at a pH = 11? mol/L What is the ratio of H+ ions to OH– ions at a pH = 11? :1, OR 1:
Physics
2 answers:
Hunter-Best [27]2 years ago
8 0

Answer

1.0/5

4

IlaMends

Ambitious

2.1K answers

12.9M people helped

Explanation:

When pH of the solution is 11.

..(1)

At pH = 11, the concentration of ions is .

When the pH of the solution is 6.

..(2)

At pH = 6, the concentration of ions is .

On dividing (1) by (2).

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is .

Difference between the ions at both pH:

This means that Hydrogen ions in a solution at pH = 7 has ions fewer than in a solution at a pH = 6

natima [27]2 years ago
5 0

1.) 0.00000000001

2.) 0.001

3.) 0.00000001: 1, OR  1: 100,000,000

- Chilio

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Tema [17]

Answer:410.90\times 10^{-6} V

Explanation:

Given

A=5.5 mm^2

n=919 turns/cm\approx 85400 turns/m

\omega =226 rad/s

According to the Faraday law of induction, induced emf is given by

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

Magnetic field \phi _B=B\cdot A

B=\mu _0ni=\mu _0ni_osin\left ( \omega t\right )

B=4\pi \times 10^{-7}\times 85400\times 3.08\times \sin (226t)

B=0.3305\sin (226t)

\phi _{B}=0.3305\times \sin (226t)\times 5.5\times 10^{-6}

\phi _{B}=1.818\times 10^{-6}\sin (226t)

E=-\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

E=-1.818\times 10^{-6}\times 226\cos (226t)

E=-410.90\times 10^{-6}\cos (226t)

Amplitude of EMF induced=410.90\times 10^{-6} V

8 0
3 years ago
An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

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6 0
3 years ago
1. Two magnetic north poles will do which of the following?
RoseWind [281]
Magnetic domains are which of the following?
8 0
3 years ago
Un protón se acelera por una diferencia de potencial de 2.6k V y se dirige a una región donde existe un campo magnético uniforme
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With this information we can calculate the velocity of the proton by taking into account the kinetic energy of the proton:

qV=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(1.6*10^{-19}C)(2.6*10^3V)}{1.67*10^{-27}kg}}=705835.3m/s

The magnitude of the magnetic force will be:

F=qvB=(1.6*10^{-19}C)(705835.3m/s)(4.5T)=5.08*10^{-13}N

hope this helps!

7 0
3 years ago
The rumble feature on a video game controller is driven by a device that turns electrical energy into mechanical energy. This de
AnnyKZ [126]

Answer:

MOTOR

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The device which changes electrical energy into mechanical energy is known as motor

6 0
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