Tonya's homework assignment has four problems a, b, c, d. Her teacher instructed her to simplify each expression and then find out its value. The value of a is 3/28, the value of b is 1/2, the value of c is 15/56 and the value of d is 1/15.
Each problem has two fractions. They are given below and should be simplified.
a) 2/7 × 3/8 = 1/7 × 3/4 = 3/28
b) 2/3 × 3/4 = 1/1 × 1/2 = 1/2
c) 3/7 × 5/8 = 15/56
d) 3/10 × 2/9 = 1/5 × 1/3 = 1/15
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Answer:
c is all the points in the open interval (0,25)
Step-by-step explanation:
Here given is a function
, which is continuous in the interval [0,25] and differentiable in (0,25)
Mean value theorem says there exists at least one c in the interval (0,25) such that
We have
For the given function
Hence we have c equals all the points in the open interval (0,25)
Answer:
Your data is not accurate...
This does not look easy to factor, so I'd suggest using the quadratic formula:
-1 plus or minus sqrt( 1-4(3)(-5) )
x = -----------------------------------------------
2*3
-1 plus or minus sqrt(61)
= ------------------------------------
6
Thus, there are 2 real, unequal, irrational roots / solutions.
