Answer:
1.66
Step-by-step explanation:
Calculation to find the standard deviation for the random variable X of the number of students who work full time in samples of size
Using this formula
Standard deviation(X)=√np(1−p)
Where,
n represent the number of students=16
p represent the percentage of all students who work full time=22
Let plug in the formula
Standard deviation(X)=√16(0.22)(1−0.22)
Standard deviation(X)=√(3.52)(0.78)
Standard deviation(X)=√2.7456
Standard deviation(X)=1.656
Standard deviation(X)=1.66 (Approximately)
Therefore the standard deviation for the number of students who work full time in samples of size 16 will be 1.66
Area of a square = length²
A = x²
16 = x²; x = 4
dA/dx = 2x cm²/s
dx/dt = 6 cm/s
Using chain rule:
dA/dt = dA/dx * dx/dt
dA/dt = 2x * 6
dA/dt = 12x
At x = 4,
dA/dt = 12(4) = 48 cm²/s
For
to be continuous at
, we need to have
Note that
means that
, but that
is *approaching* 5. We're told that for
, we have
We can write
and the limit would be
and so
is discontinuous.
Answer:
a 1/3 5/3 is right i just did this
Step-by-step explanation:
