The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes = 

Distance covered by a scuba diver in 2.6 minutes = 

Rate of a scuba diver ascending for 2 minutes = 

Distance covered by a scuba diver in 2 minutes = 

The position of scuba diver after 4.6 minutes relative to sea level:

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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The long answer is <span>28.571428%, but I would round it upwards to make it seem more realistic.</span>
Step-by-step explanation:
la 6 es la mejor rspuesta
Hey there
5/12 times 3 = 5/4
5/4 is an improper fraction
so it is changed to <span>= 1 1/4</span>
The answer is 1 1/4
hope this helps you
Answer:
0.05357142
Step-by-step explanation: