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2 years ago

Why...WHY..............

Mathematics

2 answers:

mars1129 [50]2 years ago

8 0

Answer:

because I said so....that's why

svetlana [45]2 years ago

3 0

Answer:

BECAUSE TEACHERS WANT US TO SUFFER

Step-by-step explanation:

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from the edge of a cliff 180m high, the angles of depression of two boats at sea are 43° and 52° respectively what is the distan

MrRa [10]

tan 52 = 180/a; a = 180/tan 52

tan 43 = 180/b; b = 180/tan 43

you need to calculate, a-b = 180/tan 52 - 180/tan 43

substitute the value of tan thetas, and calculate it simply...

8 0

3 years ago

Garden A has 9 more currant bushes than Garden B. If 3 currant bushes are transplanted from Garden B to Garden A, then Garden A

marusya05 [52]

Answer:

Step-by-step explanation:

Let x = the original number of bushes in garden A

Let x-9 = the original number of bushes in garden B

x-9-3=x-12 = bushes in garden B after transplanting 3

x+3 = bushes in garden A after transplanting 3

x+3=1.5(x-12)

x+3=1.5x-18

0.5x=21

x=42

There were 42 current bushes in garden A

3 0

3 years ago

Read 2 more answers

What is the value of x? Enter your answer in the box. X =

melamori03 [73]

Answer:

x=54

Step-by-step explanation:

2x + 2 = 3x - 52

subtract 2x from both sides, now u have:

2 = x - 52

add 52 from both sides, now u have

54 = x

7 0

2 years ago

Find the value of X and the value of Y. (10 POINTS)

Ganezh [65]

sin 45 = opp/hyp

sin 45 = 4 / y

y = 4/sin 45

y = 4 /((sqrt2)/2)=4* sqrt(2)

tan 45 =opp/adj

tan 45 = 4/(x-3)

1 = 4/(x-3)

x-3 = 4

x=7

3 0

3 years ago

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0

1 year ago