Since this culture of bacteria obeys the law of uninhibited growth. Given that 500 bacteria are present initially, and there are 800 after 1 hour, a growth rate of 0.470003629246 (k value) has been calculated. <span>5243 </span>will be present after 5 hours.
Answer:
Total 25.45 hours will be taken to empty the pool.
Step-by-step explanation:
Time taken by large pumpkin to empty the pool=40 hours
Time taken by the smaller pumpkins to empty the pool=70 hours
Amount of pool emptied by large pumpkin in one hour=
Amount of pool emptied by small pumpkin in one hour=
Amount of pool emptied in one hour if both pumpkins work together=
+ 
=
Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . 
Total 25.45 hours will be taken to empty the pool.
Answer:
2,800
Step-by-step explanation:
Answer:
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Step-by-step explanation:
The answer is,
4.53
Answer:it goes up by 2 so it would be 3+2 is 5 5+2=7 and so on
Step-by-step explanation: