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3 years ago

HELP ME solve for X

Mathematics

1 answer:

Tanya [424]3 years ago

8 0

Answer:

203/11x

Step-by-explanation: I am soo very sorry gave you the wrong answer before but going over it I see it is 203/11x

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guapka [62]

Let p = the number of pennies
let q = the number of quarters

p + q = 23
0.01p + 0.25q = 3.11

3 0

2 years ago

Just by looking at the graph, does the graph represent a proportional relationship?

Roman55 [17]

Answer: Yes, because with each round table, the amount of chair goes up by 5.

4 0

3 years ago

Mr. Jackson orders a lunch special. The cost of each lunch is $6.00. The delivery man charges $2.00 for delivery. Complete the t

romanna [79]

Answer:

$8.00

$32.00

$62.000

N.$6.00 + $2.00

Step-by-step explanation:

6 0

3 years ago

A store sells gift cards in preset amounts.You can purchase gift cards for $10 or $25. You have spent $285 on gift cards. Erie a

pav-90 [236]

Answer:

10x + 25y = 285

One $25 gift cards with 26, $10 gift cards.

Three $25 gift cards with 21, $10 gift cards and

Five $25 gift cards with 16, $10 gift cards.

Step-by-step explanation:

I can purchase gift cards for $10 or $25. I have spent $285 on gift cards.

If I have purchased x number of $10 gift cards and y number of $25 gift cards then the equation that models the situation in standard form will be given by

10x + 25y = 285 .......... (1)

Now, for y = 1, x = 26

For, y = 3, x = 21

For, y = 5, x = 16

So, here are the three combinations of gift cards that I could have purchased.

One $25 gift card with 26, $10 gift cards.

Three $25 gift cards with 21, $10 gift cards and

Five $25 gift cards with 16, $10 gift cards. (Answer)

8 0

3 years ago

Factorise x^12 y^4 - x^4 y^12<br><br>PLEASE PLEASE explain in step by step Pleasseeeeee

QveST [7]

Answer:

Step-by-step explanation:

First, look at your terms. You have two terms and two variables in each. So they can be factored out because you can distribute them back in easily.

Focus one variable first, x. You cant factor an x^12 out of an x^4. You can, but you really don't want to, it'll turn your problem into a mess. So the only thing you can do is factor out the lower exponent, x^4.

$x^4(x^8y^4-y^1^2)$

We arent done yet because the terms still share the y variable. You cant factor a y^12 from a y^4. This is the same problem with the x variable. So take out the lower one, y^4.

$x^4y^4(x^8-y^8)$

8 0

3 years ago